JS comparison of two number of size instances _javascript tips

Under normal circumstances:

if (2 >)
{
alert ("Incorrect!");
} 

This comparison will not be the desired result: it is equivalent to 2 >1, comparing the first bit of 10 out.

Workaround:

if (eval (2) > eval)
{
alert ("Incorrect!");
} 

The eval () function is used to compute a code string without referencing any particular object.

<script>  
 function  Check ()  
 {  
 var  num1=document.form1.num1.value;  
 var  num2=document.form1.num2.value;  
 if (NUM2>NUM1)  <!-error notation-->
 {  
 alert (' num2  >  num1! ');  
 return  false;  
 }  
 return  true;  
 }  
 </script> 


<script>  
 function  Check ()  
 {  
 var  num1= Document.form1.num1.value;  
 var  num2=document.form1.num2.value;  
 if (parseint (num2) >parseint (NUM1))  <!-correct notation (converted to int)-->
 {  
 alert (' num2  >  num1! ');  
 return  false;  
 }  
 return  true;  
 }  
 </script> 

EG:

110 and 18 are 18 large in the program you're writing, because

These two numbers are strings, and 1 and 1 are equal after 1 and 8, of course 8, so 18 large

You convert to int before comparing

if (parseint (num2) >parseint (NUM1))

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