JS validation date format various code

Example 1

Verify YYYY-MM-DD date format, do not validate incorrect dates such as "2012-11-45"

The code is as follows

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<script language= "JavaScript" > function Formattime (str) { var r = Str.match (/^ (d{1,4}) (-|/) (d{1,2}) 2 (d{1,2}) $/); if (r==null) return false; var d= new Date (r[1], r[3]-1, r[4]); Return (D.getfullyear () ==r[1]&& (D.getmonth () +1) ==r[3]&&d.getdate () ==r[4]); } function Checkdata (cform) { if (document.vbform.bdaynew.value== "") { Alert ("The due date cannot be empty, please enter!") "); Document.vbform.bdaynew.focus (); return false; } if (!formattime (Cform.bdaynew.value)) { Alert ("Up to date format error!") "); Cform.bdaynew.focus (); return false; } return true; } </script> <form name= "Vbform" onsubmit= "Return to Checkdata (this);" > <input name= "bdaynew" type= "text" size= "" class= "Input" > <span style= "color: #FF0000" > Time format is 2007-01-01 or 2007-1-1</span> </form>

If I were in the 2013/01/01 format,

The code is as follows

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Determine if input is a date function isdatestring (sdate) { var mp=/d{4}-d{2}-d{2}/;    var Matcharray = Sdate.match (MP);    if (matcharray==null) return false;    var iamonthdays = [31,28,31,30,31,30,31,31,30,31,30,31];    var iadate = new Array (3);    var year, month, day;          iadate = Sdate.split ("/"); &N bsp; //Here we can automatically modify-can also be: Oh.       year = parsefloat (iadate[0])     month = parsefloat (iadate[1]) &NB sp;   day=parsefloat (iadate[2])     if (Year < 1900 | | year > 2100) return false;     if ((year% 4 = 0) && (year% 100!= 0) | | (Year% 400 = 0)) iamonthdays[1]=29;     if (Month < 1 | | month >) return false;     if (Day < 1 | | day > IAMONTHDAYS[MONTH-1]) return false;     return true; }

Use
if (!isdatestring (complete_date))
{
Alert ("The actual finish date is not in the correct format and the date format is Yyyy-mm-dd");
Return
}

Long time, shaped like (2003-12-05 13:04:06)

The code is as follows

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function Strdatetime (str)        {           var reg =/^ (d{1,4}) (-|/) (d{1,2}) 2 (d{1,2}) (d{1,2}):(d{1,2}):(d{1,2}) $/;          var r = Str.match (reg);          if (r==null) return false;          var d= new Date (r[1], r[3]-1,r[4],r[5],r[6],r[7]);          return (D.getfullyear () ==r[1]&& (D.getmonth () +1) ==r[3 ]&&d.getdate () ==r[4]&&d.gethours () ==r[5]&&d.getminutes () ==r[6]&&d.getseconds () ==R[7]); }