A city's skyline is the outer contour of the silhouette formed by all the buildings in then city then viewed from a Distan Ce. Now suppose you is given the locations and height of all the buildings as shown in a cityscape photo (figure A), write a Program to output the skyline formed by these buildings collectively (Figure B).
The geometric information of each building was represented by a triplet of integers [Li, Ri, Hi]
, where and is the Li
Ri
x Coordinates of the left and right edge of the ith building, respectively, and are its Hi
height. It's guaranteed that 0 ≤ Li, Ri ≤ INT_MAX
, 0 < Hi ≤ INT_MAX
and Ri - Li > 0
. Assume all buildings is perfect rectangles grounded on a absolutely flat surface at height 0.
For instance, the dimensions of all buildings in Figure A is recorded as: [ [2 9 10], [3 7 15], [5 12 12], [15 20 10], [19 24 8] ]
.
The output is a list of "key points" (Red dots in Figure B) in the format of that [ [x1,y1], [x2, y2], [x3, y3], ... ]
uniquely defines a skyline. A key point was the left endpoint of a horizontal line segment. Note the last key point, where the rightmost building ends, was merely used to mark the termination of the skyline, an D always have zero height. Also, the ground in between any and adjacent buildings should is considered part of the Skyline Contour.
For instance, the skyline in Figure B should is represented as: [ [2 10], [3 15], [7 12], [12 0], [15 10], [20 8], [24, 0] ]
.
Notes:
- The number of buildings in all input list is guaranteed to being in the range
[0, 10000]
.
- The input list is already sorted in ascending order by the left X position
Li
.
- The output list must is sorted by the X position.
- There must is no consecutive horizontal lines of equal height in the output skyline. For instance, was not
[...[2 3], [4 5], [7 5], [11 5], [12 7]...]
acceptable; The three lines of height 5 should being merged into one in the final output as such:[...[2 3], [4 5], [12 7], ...]
Credits:
Public classSolution { Publiclist<int[]> Getskyline (int[] buildings) { /*this question has a very ingenious idea: discretization. What do you mean? Since the high and the left and right borders of each building are integers, it is advisable to put the line segment on the whole point. Since the last one is for a contour, the highest point of the ordinate (height) is recorded for each horizontal axis. The last one is scanned from left to right and outputs when the height is changed. But [[0,2147483647,2147483647]] results will be tle*/Map<Integer,Integer> map=NewHashmap<integer,integer>(); List<int[]> res=Newarraylist<int[]>(); if(buildings==NULL|| buildings.length<=0)returnRes; //int h[]=new int[buildings[buildings.length-1][1]]; for(inti=0;i<buildings.length;i++){ for(intj=buildings[i][0];j<buildings[i][1];j++){ if(!map.isempty () &&Map.containskey (j)) { intH=Map.get (j); H=math.max (buildings[i][2],h); Map.put (J,H); }Else{map.put (j,buildings[i][2]); } } } for(intI=1;i<map.size (); i++){ if(Map.get (i)!=map.get (i-1) {Res.add (New int[]{i,map.get (i)}); } } returnRes; }}
[Leedcode 218] The Skyline problem