[Leetcode]: 242:valid anagram

Source: Internet
Author: User


Given, Strings s and T, write a function to determine if it is a anagram of s.

For example,
s = "Anagram", t = "Nagaram", return true.
s = "Rat", t = "Car", return false.


Criteria for distinguishing "anagram":

1. Two characters are exactly equal and two numbers are completely empty: true

2. Two characters unequal length: false

3. The number of occurrences of the same character is not equal: false

The code is as follows:

 Public classSolution { Public Static inthascharacter (String Basic, String Target) { for(inti = 0;i<basic.length (); i++){            if(Basic.substring (i, i+1) = =Target) {                returni; }        }                return-1; }         Public Static BooleanIsanagram (string s, String t) {if(S.length ()! =t.length ()) {            return false; }                if(s = =t) {            return true; }                 for(intI=0;i<t.length (); i++){            intIflag = Hascharacter (s,t.substring (i, i+1)); if(Iflag = =-1){                return false; }            Else{s= S.substring (iflag,iflag+1); }        }        return true; }}

Master's idea: convert two characters to a string and then compare them after sorting

     Public Static BooleanIsanagram (string s, String t) {if(s = = T | | (S.equals ("") && t.equals (""))){            return true; }                if(S.length ()! =t.length ()) {            return false; }                Char[] CharS =S.tochararray (); Char[] CharT =T.tochararray ();        Arrays.sort (CharS);                Arrays.sort (CharT); returnchars.equals (CharT); }

[Leetcode]: 242:valid anagram

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