Transmission Door
Given a list of unique words. Find all pairs of distinct indices (i, j)
in the given list, so, the concatenation of the-words, i.e. is a palindrome.
Example 1:
Given words
=["bat", "tab", "cat"]
Return[[0, 1], [1, 0]]
The palindromes is["battab", "tabbat"]
Example 2:
Given words
=["abcd", "dcba", "lls", "s", "sssll"]
Return[[0, 1], [1, 0], [3, 2], [2, 4]]
The palindromes is["dcbaabcd", "abcddcba", "slls", "llssssll"]
Credits:
Special thanks to @dietpepsi for adding this problem and creating all test cases.
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Test instructions: Give a dictionary with n words, ask how many different combinations of two words make the new combination of words is palindrome string.
Idea: For each word, from left to right to iterate over, for any position, if its left is a palindrome string and the right side of the reverse in the dictionary appears, then there is such a combination, similarly, if its right is a palindrome string and the left side of the reverse in the dictionary appears, then there is such a combination.
It's a good question, it involves a lot of knowledge.
But there is a small doubt, why use a map to time out, with Unordered_map on the
chaotic map of Stl::unordered_map
http://blog.csdn.net/devourheavens/article/details/7539815
A hash map is an associative container that stores elements through key values and mapped values . Allows quick retrieval of individual elements based on key values.
In Unordered_map, a key value is typically used to uniquely identify an element, and the corresponding value is the content of an object associated with that key. The type of the key mapping value may vary. Elements in the internal unordered_mapNoAn element with a key value or a mapmake any particular sort of orderItsThe storage location depends on the hash value allowing for fast access to a single element (with a constant average time complexity) directly through its key value. UNORDERED_MAP container than Map containeraccess their individual elements faster with key values, although unordered_map is generally more than a subset of the map through its elements rangeLow Iteration efficiency。 Hash map allows you to use the operator operator (operator []) to directly access an element with its key value as a parameter.
Submission Details
134/134 Test cases passed. |
status:accepted |
runtime:1804 ms |
1 classSolution {2 Public:3vector<vector<int>> Palindromepairs (vector<string>&words) {4vector<vector<int> >ans;5unordered_map<string,int>MP;6 intn =words.size ();7 inti,j;8 for(i =0; I < n;i++){9mp[Words[i]] =i;Ten } One A for(i =0; I < n;i++){ - intL =words[i].length (); - if(L = =0){//empty string the for(intK =0; k < n;k++) - if(k! = I && ISPA (Words[k])) Ans.push_back (vector<int>{i,k}); - Continue; - } +Mp.erase (Words[i]);//It is a palindrome, which can cause errors. - for(j =0; J < L;j + +){ + stringSubl = Words[i].substr (0, J); A stringSUBR =words[i].substr (j,l); at stringREVL,REVR; - revl.assign (Subl.rbegin (), Subl.rend ()); - revr.assign (Subr.rbegin (), Subr.rend ()); - //J Left is a palindrome, and J right side is found in reverse order (including J) - if(Mp.find (REVR)! = Mp.end () &&ISPA (SUBL)) { -Ans.push_back (vector<int>{mp[revr],i}); in } - //J Right is a palindrome, and J left side is found in reverse order (including J) to if(Mp.find (REVL)! = Mp.end () &&ISPA (SUBR)) { +Ans.push_back (vector<int>{I,MP[REVL]}); - } the } *mp[Words[i]] =i; $ }Panax Notoginseng returnans; - } the BOOLIspastring&s) + { A inti =0; the intL =s.length (); + intj = L-1; - while(I <=j) { $ if(S[i]! = S[j])return false; $i++;j--; - } - return true; the } -};
string of C++stl
http://blog.csdn.net/y990041769/article/details/8763366
Http://www.cnblogs.com/aicro/archive/2010/01/15/1642659.html
A) =,assign ()//Assign new value
S.assign (b,e); Replace s with elements in the iterator B to e range
Introduction to common operation of STL map
Http://www.cnblogs.com/TianFang/archive/2006/12/30/607859.html
7. Delete an element from the map
Remove an entry from a map with erase ()
The member method is defined as follows
- Iterator Erase (iterator it); Delete by an Entry object
- Iterator Erase (iterator first, iterator last); Delete a range
- Size_type Erase (const key& Key); Delete by keyword
Clear () is equivalent to Enummap.erase (Enummap.begin (), Enummap.end ());
Leetcode 336. Palindrome Pairs