373. Find K Pairs with smallest Sums
- Total accepted:1453
- Total submissions:5789
- Difficulty:medium
You are given the integer arrays nums1 and nums2 sorted in ascending order and an integer k.
Define a pair (U,V) which consists of one element from the first array and one element from the second array.
Find the K pairs (U1,V1), (U2,V2) ... (UK,VK) with the smallest sums.
Example 1:
Given NUMS1 = [1,7, One], NUMS2 = [2,4,6], k =3Return: [1,2],[1,4],[1,6]the First3Pairs is returned fromThe sequence:[1,2],[1,4],[1,6],[7,2],[7,4],[ One,2],[7,6],[ One,4],[ One,6]
Example 2:
Given NUMS1 = [1,1,2], NUMS2 = [1,2,3], k =2Return: [1,1],[1,1]the First2Pairs is returned fromThe sequence:[1,1],[1,1],[1,2],[2,1],[1,2],[2,2],[1,3],[1,3],[2,3]
Example 3:
Given nums1 = [1,2], NUMS2 = [3], 3 Return: [1,3],[ 2,3 from the sequence:[1,3],[2 ,3]
Ideas:
Method One: The pair (NUM1,NUM2) is inserted directly into the priority_queue, the elements of the priority queue are sorted in ascending order of num1+num2, and the Last min (Nums1.size () *nums2.size (), K) is returned.
Method Two: Optimization of method one.
Method Three: Nums1 each element in the NUM1 retains an array of the corresponding NUMS2 element num2 position index. Each time you traverse each element in the NUMS1, for the element in Nums1 Nums1[i], in NUMS2 with Nums2[index[nums1[i]]], take the smallest nums1[i]+nums2[index[nums1[i]], and then ( Nums1[i],nums2[index[nums1[i]]) is inserted into the vector of the result.
You can refer to the usage of priority_queue for the use of priority_queue.
Code:
Method One:
1 classSolution {2 Public:3 structcmp{4 BOOL operator() (pair<int,int> num1,pair<int,int>num2) {5 //The priority_queue comparison function uses the less function:6 //returns True when the NUM1 priority is lower than num2 (NUM1 ranked behind num2)7 returnnum1.first+num1.second>num2.first+Num2.second;8 }9 };Tenvector<pair<int,int>> Ksmallestpairs (vector<int>& Nums1, vector<int>& Nums2,intk) { Onevector<pair<int,int>>Res; Apriority_queue<pair<int,int>,vector<pair<int,int>>,cmp>PQ; - intI,j,m=nums1.size (), n=nums2.size (); - for(i=0; i<m;i++){ the for(j=0; j<n;j++){ - Pq.push (Make_pair (nums1[i],nums2[j)); - } - } + while(k-->0&&pq.size () >0){ - Res.push_back (Pq.top ()); + Pq.pop (); A } at returnRes; - } -};
Method Two:
1 classSolution {2 Public:3 structcmp{4 BOOL operator() (pair<int,int>& NUM1, pair<int,int>&num2) {5 returnNum1.first + Num1.second < Num2.first +Num2.second;6 }7 };8vector<pair<int,int>> Ksmallestpairs (vector<int>& Nums1, vector<int>& Nums2,intk) {9vector<pair<int,int>>Res;Tenpriority_queue<pair<int,int, vector<pair<int,int>, cmp>PQ; One for(inti =0; I < min ((int) Nums1.size (), k); i++){ A for(intj =0; J < min (int) Nums2.size (), k); J + +){ - if(Pq.size () <k) - Pq.push (Make_pair (Nums1[i], nums2[j])); the Else if(Nums1[i] + nums2[j] < Pq.top (). First +Pq.top (). Second) { - Pq.push (Make_pair (Nums1[i], nums2[j])); - Pq.pop (); - } + } - } + while(!Pq.empty ()) { A Res.insert (Res.begin (), Pq.top ()); at Pq.pop (); - } - returnRes; - } -};
Method Three:
1 classSolution {2 Public:3vector<pair<int,int>> Ksmallestpairs (vector<int>& Nums1, vector<int>& Nums2,intk) {4vector<pair<int,int>>Res;5 intI,j,m=nums1.size (), n=nums2.size ();6vector<int> Index (M,0);7K=min (k,m*n);8 while(k-->0){9 inttemp;Ten Long Longminv=Long_max; One for(i=0; i<m;i++){ A if(index[i]<n&&minv>nums1[i]+Nums2[index[i]]) { -minv=nums1[i]+Nums2[index[i]]; -temp=i; the } - } - Res.push_back (Make_pair (nums1[temp],nums2[index[temp])); -index[temp]++; + } - returnRes; + } A};
Leetcode 373. Find K Pairs with smallest Sums