Leetcode OJ binary Tree Paths (binary path)

Source: Internet
Author: User

Topic:

Given a binary tree, return all root-to-leaf paths.

For example, given the following binary tree:

   1/   2     3   5

All root-to-leaf paths is:

["1->2->5", "1->3"]
Ideas:

Pre-order recursion can be.

Code Listing 1:

/** * Definition for a binary tree node. * struct TreeNode {* int val; * TreeNode *left; * TreeNode *right; * TreeNode (int x): Val (x), left (NULL) , right (NULL) {}}; */class solution {public:vector<string> binarytreepaths (treenode* root) {vector<string> result        ;        if (root = NULL) return result;        string path;        Binarytreepaths (root, result, path);    return result;            } void Binarytreepaths (treenode* root, vector<string> &result, string path) {if (root = = NULL)        Return        if (Path.empty ()) path + = to_string (root->val);            else {path + = ";        Path + = to_string (root->val);            } if (root->left = = NULL && Root->right = = null) {result.push_back (path);        Return        } binarytreepaths (Root->left, result, path); Binarytreepaths (Root->right, result , path); }};


Code Listing 2:

/** * Definition for a binary tree node. * struct TreeNode {*     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode (int x): Val (x), left (NULL) , right (NULL) {}}; */class Solution {public:    vector<string> binarytreepaths (treenode* root)     {        vector<string> result;        if (root = NULL)            return result;        string path;        Binarytreepaths (root, result, path);        return result;    }    void Binarytreepaths (treenode* root, vector<string> &result, string path)     {        if (root = NULL)            return;        if (Root->left = = NULL && Root->right = = null)        {            result.push_back (path + to_string (root->val ));            return;        }        Binarytreepaths (root->left, result, path + to_string (root->val) + "-");        Binarytreepaths (root->right, result, path + to_string (root->val) + "-");    }};


Copyright NOTICE: Reprint please indicate the source.

Leetcode OJ binary Tree Paths (binary path)

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.