Leetcode--Plus One

Source: Internet
Author: User


Given a non-negative number represented as an array of digits, plus one to the number.

The digits is stored such, the most significant digit was at the head of the list.


A non-negative number is represented by an array, and then the number is added one.

This topic mainly needs to consider special cases: the numbers are all 9; some of the numbers are 9; the general situation. So take all the circumstances into account and OK.


 Public classSolution { Public int[] PlusOne (int[] digits) {        if(Digits = =NULL)            return NULL; if(digits[digits.length-1]! = 9) {Digits[digits.length-1] + +; returndigits; }        BooleanFlag =true;  for(inti=0; i<digits.length; i++) {            if(Digits[i]! = 9) {flag=false;  Break; }        }        if(Flag = =true) {//9 of all digits            int[] res =New int[Digits.length + 1]; res[0] = 1; returnRes; }        Else{//the last one is 9             for(intI=digits.length-1; i>=0; i--) {                if(Digits[i] = = 9) Digits[i]= 0; Else{Digits[i]++; returndigits; }            }        }        returndigits; }    }

Leetcode--Plus One

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