Leetcode#165compare Version Numbers

Compare numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return-1, otherwise ret Urn 0.

Assume that the version strings is non-empty and contain only digits and the.Character.
The.Character does not represent a decimal point and was used to separate number sequences.
For instance,2.5is not "both and a half" or "half-to-version three", it is the fifth Second-level revision of the second first-level re Vision.

Here are an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Main problem input string there are several cases

1. A string that does not contain a.

2. A string containing multiple points

3. A 0 suffix exists after a string that contains a point, for example, a comparison of 1.0.0 and 1

For a string. operation, when using split to cut the string, pay attention to the need to add "\ \"

public class Solution {

public int Compareversion (string version1, String version2) {

String w1[]=version1.split ("\ \");

String w2[]=version2.split ("\ \");

int l1=w1.length;

int l2=w2.length;

int l=l1;

if (L2<L1)

L=L2;

int i=0;

for (i=0;i<l;i++)

{

int A=integer.parseint (w1[i]);

int B=integer.parseint (w2[i]);

if (a<b)

return-1;

if (a>b)

return 1;

}

if (L1<L2)

{

for (i=l;i<l2;i++)

if (Integer.parseint (W2[i]) >0)

return-1;

return 0;

}

else if (L1>L2)

{

for (i=l;i<l1;i++)

if (Integer.parseint (W1[i]) >0)

return 1;

return 0;

}

Else

return 0;

}

}

Leetcode#165compare Version Numbers