Leetcode:minimum Moves to Equal Array Elements

Source: Internet
Author: User

Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, whe Re a move is incrementing n-1 elements by 1. example:input:[]output:3explanation:only three moves is needed (remember each move increments (elements): [[+] = [  2,3,3] = [3,4,3] = [  4,4,4]

Idea 1:suppose It takes y steps to equal each elements and then this equation stands:

(min + y) * Num.length = = sum + (num.length-1) *y, where min + y is each element's value when all elements equal

Idea 2:add 1 n - 1 to elements are the same as subtracting from one 1 element, w.r.t goal of making the elements I n the array equal.
So, the best-of-the-elements in the array equal to the min element.
sum(array) - n * minimum

1  Public classSolution {2      Public intMinmoves (int[] nums) {3         if(nums==NULL|| nums.length==0)return0;4         intMin =Integer.max_value;5         intsum = 0;6          for(intnum:nums) {7Min =math.min (min, num);8Sum + =num;9         }Ten         returnSum-min *nums.length; One     } A}

Leetcode:minimum Moves to Equal Array Elements

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