Lintcode Space Substitution

Replace spaces in a string

design a method that replaces all the spaces in a string with %20 . You can assume that the string has enough space to add new characters, and you get the "real" character length.

Class Solution {public:    /**     * @param string:an array of Char     * @param length:the True length of the string
   * @return: The true length of new string     *    /int Replaceblank (char string[], int length) {        //Write your COD e here for                (int i = 0;i < length; i++) {            if (string[i] = = ") {for                (int j = length+2; j > i+2; j--) {
   STRING[J] = string[j-2];                }                String[i] = '% ';                String[i+1] = ' 2 ';                STRING[I+2] = ' 0 ';                length = length+2;            }        }        return length;    }};  

Lintcode Space Substitution