The problem is as follows:
The three men argued in the park who were the smartest to lose. An old man came to wear a hat and said that I have five hats, three black hats and two white hats. I will bring them to you, you can only see the hats of the other party. Whoever says what color he is wearing is the smartest. The old man put on a black hat for all three people. After a while, someone guessed what he was wearing. He told the old man to wear his poetry black hat, how can I guess this person?
The problem is analyzed as follows:
For convenience, we call the three persons A, B, and C respectively.
The abbreviation of Black is B, and that of white is W.
Here we use a for analysis (centered on a). The same applies to B and C.
A, B, and C have the following possibilities:
A B C
① B
② B W
③ W B W
④ W B
First case:
A sees that both B and C are black. A will hesitate to think about whether it is white or black...
Similarly, B and c both think about it,
Since everyone is thinking about it, no one will quickly say the color of his hat, so a considers himself as black.
Case 2:
There are only two white ones in total. If a sees that B and C are both white, it is very sure that they are black.
Third case:
In the second case, B should be able to quickly say that he is black.
Case 4:
A sees that B and C are black. A will hesitate to think about whether he is wearing white or black...
B sees that A is white, C is black, and B will hesitate to think about whether he is wearing white or black, because B cannot determine whether he is wearing another white hat, if B can see that C is also white, then the answer is revealed.
C is the same as B's, and B's thinking is the same. So again, everyone is hesitating to think...
The analysis ends with such a game,
Someone must be able to quickly say that they are wearing a black hat!