(mathematics) Hdu 1205

Source: Internet
Author: User

Eat candy

Time limit:6000/3000 MS (java/others) Memory limit:65535/32768 K (java/others)
Total submission (s): 26515 Accepted Submission (s): 7533

Problem Descriptionhoho, finally from Speakless hand to win all the candy, is Gardon eat candy when there is a special hobby, is not like the same candy put together to eat, like to eat first, the next time to eat another, so But Gardon don't know if there is a candy-eating order so he can finish all the candies? Please write a program to help calculate.

Input first line has an integer t, the next T-group data, each group of data accounted for 2 rows, the first row is an integer n (0<n<=1000000), the second row is n number, indicating the number of n candies Mi (0<mi<=1000000).

Output for each set of data, outputs a line that contains a "Yes" or "No".

Sample Input234 1 155 4 3 2 1

Sample Outputnoyes HintHintplease Use function scanf


Sourcegardon-dygg Contest 2

recommendjgshining | We have carefully selected several similar problems for you:1201 1021 1008 1234 1071
#include <iostream> #include <cstdio> #include <cstring> #include <string> #include <cmath > #include <cstdlib> #include <algorithm>using namespace std; #define LL long Longint Tt,n,maxx; LL Sum;int Main () {    int x;    scanf ("%d", &tt);    while (tt--)    {        sum=0,maxx=0;        scanf ("%d", &n);        for (int i=1;i<=n;i++)        {            scanf ("%d", &x);            sum+=x;            if (X>maxx)                maxx=x;        }        if (2*maxx-sum<=1)            printf ("yes\n");        else            printf ("no\n");    }    return 0;}


(mathematics) Hdu 1205

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