1. Method Function Description
Ordered Set: (A, B, C, D, E, F, G, H, I, J), there are already segments (only the beginning and end): (A, D ), (G, H ).
Function: Find other segments (D, G), (H, J ).
For example, in the competition track, from location A to location J, it must pass through B, C, D, E, F, G, H, I, J, divide the orbit into several segments (with only the beginning and end): (A, D), (D, G), (G, H), (H, J ). Now we already have segments (A, D), (D, G). How can we find segments (G, H), (H, J )?
2. Code Description and description
(1) thoughts
Loop string, which compares to the first character of the substring one by one,
If the sub-string list does not exist, add the Sub-string and set the first character of the sub-string to this string;
If this character exists in the substring, the last character of the substring is obtained and the segment is skipped cyclically.
(2) C # code
1 private List<List<string>> FillMidList(List<string> stringList, List<List<string>> midList)
2 {
3 List<List<string>> rtn = new List<List<string>>();
4 List<string> strList = null;//Char List
5 string start = string.Empty;//Start Char
6 string end = string.Empty;//End Char
7 bool isFind = false;
8 bool isFindEnd = false;//Find End Char
9
10 for (int i = 0; i < stringList.Count; i++)
11 {
12 start = stringList[i];
13 //If exit char
14 foreach (var item in midList)
15 {
16 if (start == item[0])
17 {
18 if (isFindEnd == true)
19 {
20 end = start;
21 }
22 isFind = true;
23 start = item[item.Count - 1];
24 break;
25 }
26 }
27
28 if (isFind == true)
29 {
30 isFind = false;
31 //Adjust index
32 for (int j = 0; j < stringList.Count; j++)
33 {
34 if (stringList[j] == start)
35 {
36 i = j - 1;
37 break;
38 }
39 }
40 if (isFindEnd == true)
41 {
42 strList.Add(end);
43 rtn.Add(strList);
44 isFindEnd = false;
45 end = string.Empty;
46 }
47 }
48 else
49 {
50 if (isFindEnd == true)
51 {
52 //Add the last
53 if (start == stringList[stringList.Count - 1])
54 {
55 strList.Add(start);
56 rtn.Add(strList);
57 }
58 }
59 else
60 {
61 strList = new List<string>();
62 strList.Add(start);
63 isFindEnd = true;
64 }
65 }
66 }
67
68 return rtn;
69 }
3. Description
This feature is sometimes encountered in the project process. I personally feel that it is a little complicated to write and provide a comment for your discussion.