[Noi the arithmetic expression and sequential execution of]1.3 Programming foundation of the Test Bank (I.)

The problem of A+b

The classic a+b problem--the first question on the big questions. Read into $a,b$, output $a+b$.

#include <iostream>usingnamespace  std; int Main () {    int A, b;    CIN>>a>>b;    cout<<a+b<<Endl;     return 0 ;}

01.cpp 02 Calculation (A+B) value of *c

Read into $a,b,c$, output $c (a+b) $.

#include <iostream>usingnamespace  std; int Main () {    int  a,b,c;    CIN>>a>>b>>C;    cout<< (a+b) *c<<Endl;     return 0 ;}

02.cpp 03 calculation (A+B)/C value

Read in $a,b,c$, output $\lfloor \dfrac{a+b}{c} \rfloor$. In fact, if operators are integers, the division sign "/" in C + + can be rounded up.

#include <iostream>usingnamespace  std; int Main () {    int  a,b,c;    CIN>>a>>b>>C;    cout<< (a+b)/c<<Endl;     return 0 ;}

03.cpp 04 with remainder Division

Elementary school arithmetic, set to read in is $a,b$, then the two number of the request is a/ b and a%b .

#include <iostream>usingnamespace  std; int Main () {    int A, b;    CIN>>a>>b;    cout<<a/b<<""<<a%b<<Endl;     return 0 ;}

04.cpp 05 floating-point values for the calculation of fractions

      with  double The   type stores and divides operations, noting that output is formatted as a format. Of course you can also use  1.0 *a/b   Such statements get the result of the real number except.

#include <cstdio>usingnamespace  std; int Main () {    int A, b;    scanf ("%d%d",&a,&b);    printf ("%.9f\n",1.0*a/b);     return 0 ;}

05.cpp 06 Swine Flu Epidemic mortality

      awesome backgrounds ... In fact, it is the division of two numbers, resulting in a percentage output. The output statement can be written as  printf ( %.3f%%\n , 100 *x);  ,x is a calculated quotient.

 #include <cstdio>using  namespace   Std;  int   Main () { int      b; scanf (  %d%d   ", &a,&b);    b  =b*100    %.3f%%\n   ", 1.0  *b/a);  return  0  ;}  

06.cpp 07 Calculating the value of a polynomial

This problem can be directly calculated, but there is a better way, is the law of Horner:

\[f (x) =ax^3+bx^2+cx+d= ((ax+b) x+c) x+d\]

This can reduce the number of operations.

#include <cstdio>usingnamespace  std; int Main () {    double  x,a,b,c,d;    scanf ("%lf%lf%lf%lf%lf",&x,&a,&b,&c,&D);    printf ("%.7f\n", ((* (* (x) +b) *x) +c) *x+D)    ; return 0 ;}

07.cpp 08 Temperature Expression Conversion

      give $f$, $c=\dfrac{5}{9} (F-32) $,.

 #include <cstdio>using  namespace   Std;  int   Main () { double   F,c; scanf (  %lf     , &f); C  =5  * (F-32 )/9  ; printf (  %.5f\n   " ,c);  return  0  ;}  

08.cpp 09 calculations related to the circle

Give $r$, Beg $c=2\pi R $ and $s=\pi r^2$.

 #include <cstdio> #define  PI 3.14159 namespace   Std;  int   Main () { double   R; scanf (  %lf     , &r); printf (  %.4f%.4f%.4f\n   ", 2  *r,2  *pi*r,pi*r*R);  return  0  ;}  

09.cpp 10 calculating the resistance of the shunt resistor

Give a $r_1,r_2$, beg

\[r=\frac{1}{\frac{1}{r_1}+\frac{1}{r_2}}\]

 #include <cstdio>using  namespace   Std;  int   Main () { float      R,R1,R2; scanf (  %f%f   ", &r1,&R2); R  =1.0 /(1 /r1+1 /R2); printf (  %.2f\n   " ,r);  return  0  ;}  

10.cpp

[Noi the arithmetic expression and sequential execution of]1.3 Programming foundation of the Test Bank (I.)