09-Hash 1. Hashing (25) time limit MS Memory limit 65536 KB code length limit 8000 B procedure StandardAuthor Chen, Yue
The task of this problem are simple:insert a sequence of distinct positive integers into a hash table, and output the Posi tions of the input numbers. The hash function is defined to being "H (key) = key% tsize" where tsize is the maximum size of the hash table. Quadratic probing (with positive increments only) are used to solve the collisions.
Note The table size is better to being prime. If the maximum size given by the user are not prime, you must re-define the table size to be the smallest prime number whic H is larger than the size given by the user.
Input Specification:
Each input file contains the one test case. For each case, the first line contains the positive numbers:msize (<=104) and N (<=msize) which is the User-define d table size and the number of input numbers, respectively. Then N distinct positive integers is given in the next line. All the numbers in a line is separated by a space.
Output Specification:
For each test case, print the corresponding positions (index starts from 0) of the of the input numbers on one line. All the numbers in a line is separated by a space, and there must is no extra space at the end of the line. In case it was impossible to insert the number, print "-" instead.
Sample Input:
4 410 6) 4 15
Sample Output:
0 1 4-
Submit Code
Watch the boundary test!
1#include <cstdio>2#include <algorithm>3#include <iostream>4#include <cstring>5#include <queue>6#include <vector>7 using namespacestd;8 BOOLh[10005];9 intGetnextprime (intnum) {Ten inti,j; One if(num==1){//Note the border A return 2; - } - if(num==2){//Note the border the return 2; - } - for(I=num;; i++){ - if(i%2==0){ + Continue; - } + for(j=3; j*j<=i;j+=2){ A if(i%j==0){ at Break; - } - } - if(j*j>i) { - returni; - } in } - } to intMain () { + //freopen ("D:\\input.txt", "R", stdin); - intMsize,n; thescanf"%d%d",&msize,&n); * inti,num,j; $memset (H,false,sizeof(h));Panax NotoginsengMsize=Getnextprime (msize); -queue<int>Q; the for(i=0; i<n;i++){ +scanf"%d",&num); Anum=num%msize; the if(!H[num]) { +h[num]=true; - Q.push (num); $ } $ Else{ - intNext; - for(j=1; j<=msize/2; j + +){ thenext= (num+j*j)%msize; - if(!H[next]) {Wuyih[next]=true; the Q.push (next); - Break; Wu } - } About if(j>msize/2){ $Q.push (-1); - } - } - } A intNow ; + if(!Q.empty ()) { thenow=Q.front (); - Q.pop (); $ if(now==-1){ theprintf"-"); the } the Else{ theprintf"%d", now); - } in } the while(!Q.empty ()) { thenow=Q.front (); About Q.pop (); the if(now==-1){ theprintf" -"); the } + Else{ -printf"%d", now); the }Bayi } theprintf"\ n"); the return 0; -}
pat09-Hash 1. Hashing (25)