Path Sum Total accepted:50216 Total Submissions:168425__leetcode

Source: Internet
Author: User

The title comes from Leetcode

https://leetcode.com/problems/path-sum/

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding of all the values along the Path equals the given sum. For example:
Given the below binary tree and sum = 22,

              5
             /
            4   8
           /   //  4
         /      \ + 7 2 1

Return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode (int x): Val (x), left (null), right (null) {}
 *};
 * *
class Solution {public
:
   void Psum (TreeNode *root, int sum) 
   {
       if (root!=null)
       {
          if (root->val==sum&&root->left==null&&root->right==null)
        {
            flag=true;
            return;
        }
        
          Psum (Root->left,  sum-root->val);
          Psum (Root->right,  sum-root->val);
          return false;  
       }
           
   }
    BOOL Haspathsum (TreeNode *root, int sum) {
       if (Root==null) return
        false;
         Psum (root, sum);
         return flag;
    }
    
    bool flag=false;
};


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