Topic Connection
http://poj.org/problem?id=1985
Cow marathondescription
After hearing about the epidemic of obesity in the USA, Farmer John wants his cows to get more exercise, so he had Committ Ed to create a bovine marathon for the cows to run. The marathon route would include a pair of farms and a path comprised of a sequence of roads between them. Since FJ wants the cows to get as much exercise as possible he wants to find the both farms on his map that is the farthes T apart from all other (distance being measured in terms of total length of road on the path between the same farms). Help him determine the distances between this farthest pair of farms.
Input
* Lines 1 ...: same input format as "Navigation nightmare".
Output
* Line 1:an integer giving the distance between the farthest pair of farms.
Sample Input
7 6
1 6 E
6 3 9 E
3 5 7 S
4 1 3 N
2 4 W
4 7 2 S
Sample Output
52
The diameter of the tree.
#include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include < cstdio> #include <vector> #include <queue> #include <map>using std::map;using std::min;using std:: Find;using std::p air;using std::queue;using std::vector;using std::multimap; #define PB (E) push_back (e) #define SZ (c) ( int) (c). Size () #define MP (A, b) Make_pair (A, B) #define ALL (c) (c). Begin (), (c). End () #define ITER (c) __typeof ((c). Begin () ) #define CLS (arr, Val) memset (arr, Val, sizeof (arr)) #define Cpresent (C, E) (Find (All (c), (e))! = (c). End ()) #define REP (I, n) for (int i = 0; i < (int.) n; i++) #define TR (c, I) for (ITER (c) i = (c). Begin (); I! = (c). end (); ++i) const int n = 50010 ; const int INF = 0x3f3f3f3f;struct work {struct Edge {int to, w, next;} G[n << 1]; int tot, head[n], dist[n]; inline void init () {tot = 0, CLS (Head,-1); } inline void Add_edge (int u, int v, int w) {G[tot] = (edge) {V, W, Head[u]}; head[u] = tot++; G[toT] = (edge) {u, W, Head[v]}; HEAD[V] = tot++; } inline int BFs (int s) {int id = s, max_dist = 0; CLS (Dist,-1); Queue<int> Q; Q.push (s); Dist[s] = 0; while (!q.empty ()) {int u = q.front (); Q.pop (); if (Dist[u] > max_dist) {max_dist = Dist[id = u]; } for (int i = head[u]; ~i; i = g[i].next) {Edge &e = G[i]; if ( -1 = = Dist[e.to]) {dist[e.to] = Dist[u] + e.w; Q.push (e.to); }}} return ID; } inline void solve (int m) {char ch; int U, V, W; CLS (Head,-1); while (m--) {scanf ("%d%d%d%c", &u, &v, &w, &ch); Add_edge (U, V, W); } printf ("%d\n", Dist[bfs (BFS (U))]); }}go;int Main () {#ifdef LOCAL freopen ("In.txt", "R", stdin); Freopen ("OUT.txt", "w+", stdout); #endif int N,M while (~SCANF ("%d%d", &n, &m)) {go.solve (M); } return 0;}
POJ 1985 Cow Marathon