Count Color
Time Limit: 1000MS |
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Memory Limit: 65536K |
Total Submissions: 36586 |
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Accepted: 11041 |
Description
Chosen Problem solving and program design as a optional course, you is required to solve all kinds of problems. Here, we get a new problem.
There is a very long board with length L centimeter, L was a positive integer, so we can evenly divide the board into L seg ments, and they is labeled by 1, 2, ... L from left to right, each is 1 centimeter long. Now we has to color the Board-one segment with only one color. We can do following-operations on the board:
1. "C A B C" Color the board from segment A to segment B with Color C.
2. "P A B" Output the number of different colors painted between segment A and segment B (including).
In our daily life, we had very few words to describe a color (red, green, blue, yellow ...), so if you could assume that the Tota L number of different colors T is very small. To make it simple, we express the names of colors as color 1, color 2, ... color T. At the beginning, the board is painted in color 1. Now the rest of problem are left to your.
Input
First line of input contains L (1 <= L <= 100000), T (1 <= t <=) and O (1 <= O <= 100000). Here O denotes the number of operations. Following O lines, each contains "c a b C" or "P a B" (here A, B, C is integers, and A may is larger than B) as an Operat Ion defined previously.
Output
Ouput results of the output operation in order, each line contains a number.
Sample Input
2 2 4C 1 1 2P 1 2C 2 2 2P 1 2
Sample Output
21st
Topic Meaning:
There are n pieces of wood, each piece of wood initialization color 1,m operation: C L R Val is the section L to the R section of the board dyed full color val;p l r output the number of different colors in paragraph l to section R.
Ideas:
A color of up to 30, the pressure color is OK, this paragraph has the color, then this bit is 1, otherwise 0. Line tree Each node has a flag flag, true words can be updated downward, false words cannot be updated down------interval update old routines.
Code:
1#include <cstdio>2#include <cstring>3#include <algorithm>4#include <iostream>5#include <vector>6#include <queue>7 using namespacestd;8 9 #defineN 100005Ten #definell Root<<1 One #defineRR root<<1|1 A #defineMid (A[ROOT].L+A[ROOT].R)/2 - intMaxintXintY) {returnX>y?x:y;} - intMinintXintY) {returnX<y?x:y;} the - structnode{ - intL, R, Val;//Val is the color state - BOOLFlag; +}a[n*4]; - + intn, color, m; A at voidBuildintLintRintroot) { -A[root].l=l; -A[root].r=R; -A[root].val=2;//here is the wrong one, the initialization color is 1, then the state is 1<<1 2 -a[root].flag=false; - if(L==R)return; in build (L,MID,LL); -Build (mid+1, R,RR); to } + - voidChangeintLintRintValintroot) { the if(a[root].l==l&&a[root].r==R) { *A[root].val=1<<Val; $a[root].flag=true;Panax Notoginseng return; - } the if(A[root].flag) {//if True, and the segment of the query is in this paragraph, then the update is down and flag becomes false +a[root].flag=false; A if(a[root].l!=A[ROOT].R) { theA[ll].val=a[rr].val=A[root].val; +a[ll].flag=a[rr].flag=true; - } $ } $ if(l>mid) Change (L,R,VAL,RR); - Else if(r<=mid) Change (L,R,VAL,LL); - Else{ the Change (L,MID,VAL,LL); -Change (mid+1, R,VAL,RR);Wuyi } theA[root].val=a[ll].val|a[rr].val;// up - } Wu - intFindintLintRintroot) { About if(A[ROOT].L==L&&A[ROOT].R==R)returnA[root].val; $ if(a[root].flag) { -a[root].flag=false; - if(a[root].l!=A[ROOT].R) { -A[ll].val=a[rr].val=A[root].val; Aa[ll].flag=a[rr].flag=true; + } the } - if(L>mid)returnfind (L,R,RR); $ Else if(R<=mid)returnfind (L,R,LL); the Else{ the returnFind (L,MID,LL) |find (mid+1, R,RR); the } thea[root].val=a[ll].val|A[rr].val; - } in the Main () the { About intI, J, K; the Chars[Ten]; the intx, y, Z; the while(SCANF (" %d%d%d", &n,&color,&m) = =3){ +Build1N1); - while(m--){ thescanf"%s", s);Bayi if(strcmp (s),"C")==0){ thescanf" %d%d%d",&x,&y,&z); theChange (min (x, y), Max (x, y), Z,1); - } - Else if(strcmp (s),"P")==0){ thescanf"%d%d",&x,&y); the intNum=find (min (x, y), Max (x, y),1), ans=0; the the for(i=0; i<=color;i++) { - if((1<<i) &num) ans++; the } theprintf"%d\n", ans); the }94 } the the } the}
POJ 2777-Shaped pressure line segment tree