POJ 3261 suffix array find substrings that appear repeatedly k (substrings can overlap)

Source: Internet
Author: User

Title: http://poj.org/problem?id=3261

is still a typical application of the suffix array----suffix array +lcp+ two points


That's pretty smooth, 1A.

But most of the time is debugging code. Because the template's global variables are mixed, and you forget it. ,, and so on Xi ' an invitational tournament and four provinces after the end of the calm reflection under the attempt to please template

Error: 1, k with the wrong, the title of K and the template K mixed;

2, or the second part of the C () function, this in fact, in front of a "POJ 1226 Hdu 1238 substrings to find a number of string strings and crossdress the longest common substring 2002 Asian Tianjin Pre-selected topic" C functions almost identical. But it's easier than that, but it's been a while. ,。 At the start. If RET is not recorded, the maximum value of RET should be recorded.

3,last>=kk-1 only, because Lcp[i] itself is two substrings of the public prefix length

int C (int x) {    int ret=0,last=0;    for (int i=0;i<=n;i++)    {        if (lcp[i]>=x) ret++;        else        {            Last=max (last,ret);            ret=0;        }    }    if (last>=kk-1) return 1;    else return 0;}

On the code:
#include <cstdio> #include <iostream> #include <string> #include <algorithm>using namespace std ; const int MAXN = 20200;int rk[maxn],sa[maxn],s[maxn],tmp[maxn],lcp[maxn],n,k,kk;bool cmpsa (int i,int j) {if (Rk[i]! = R    K[J]) return rk[i]<rk[j];        else {int ri = i+k<=n?rk[i+k]:-1;        int RJ = j+k<=n?rk[j+k]:-1;    Return ri<rj;    }}void Consa () {for (int i=0;i<=n;i++) sa[i]=i,rk[i]=i<n?s[i]:-1;        for (k=1;k<=n;k*=2) {sort (SA,SA+N+1,CMPSA);        tmp[sa[0]]=0;        for (int i=1;i<=n;i++) {tmp[sa[i]]=tmp[sa[i-1]]+ (CMPSA (Sa[i-1],sa[i])? 1:0);    } for (int i=0;i<=n;i++) rk[i]=tmp[i];    }}void CONSTRUCT_LCP () {//n=strlen (s);    for (int i=0; i<=n; i++) rk[sa[i]]=i;    int h=0;    lcp[0]=0;        for (int i=0;i<n;i++) {int j=sa[rk[i]-1];        if (h>0) h--;  for (; J+h<n && i+h<n; h++) {if (s[j+h]!=s[i+h]) break;      } lcp[rk[i]-1]=h;    }}int C (int x) {int ret=0,last=0;        for (int i=0;i<=n;i++) {if (lcp[i]>=x) ret++;            else {Last=max (Last,ret);        ret=0;    }} if (last>=kk-1) return 1; else return 0;}    int main () {//freopen ("Poj 3261.txt", "R", stdin);        while (scanf ("%d%d", &n,&kk)!=eof) {for (int i=0;i<n;i++) scanf ("%d", &s[i]);        S[n]=-1;        Consa ();        CONSTRUCT_LCP ();        int d=0,up=n+1,mid;            while (up>d+1) {mid= (d+up)/2;            if (C (mid)) D=mid;        else Up=mid;    } printf ("%d\n", D); } return 0;}


POJ 3261 suffix array find substrings that appear repeatedly k (substrings can overlap)

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.