Returns the difference of the greatest value in the interval.
Two Queries are used. The query time is 3 S +... so slow and fast.
#include<cstdio>#include<algorithm>#include<cstring>using namespace std;#define lson l,m,rt<<1#define rson m+1,r,rt<<1|1const int MM=1000005;const int maxn=50005;int MAX[maxn<<2],MIN[maxn<<2];void build(int l,int r,int rt){ if(l==r){ scanf("%d",&MAX[rt]); MIN[rt]=MAX[rt]; return ; } int m=(l+r)>>1; build(lson); build(rson); MAX[rt]=max(MAX[rt<<1],MAX[rt<<1|1]); MIN[rt]=min(MIN[rt<<1],MIN[rt<<1|1]);}int query1(int L,int R,int l,int r,int rt){ if(L<=l&&R>=r){ return MAX[rt]; } int m=(l+r)>>1; int ret=0; if(L<=m) ret=max(ret,query1(L,R,lson)); if(R>m) ret=max(ret,query1(L,R,rson)); return ret;}int query2(int L,int R,int l,int r,int rt){ if(L<=l&&R>=r){ return MIN[rt]; } int m=(l+r)>>1; int ret=MM; if(L<=m) ret=min(ret,query2(L,R,lson)); if(R>m) ret=min(ret,query2(L,R,rson)); return ret;}int main() { int N,Q; while(~scanf("%d%d",&N,&Q)) { build(1,N,1); while(Q--){ int a,b; scanf("%d%d",&a,&b); printf("%d\n",query1(a,b,1,N,1)-query2(a,b,1,N,1)); } } return 0;}