Interesting question.
It is not difficult to think about it. Hash is used to judge the weight, but the question is how to sort each series according to the same rule at the beginning.
For example
2 1 2 1 2
1 1 2 2 1 2
How to convert to 1 1 2 2 1 2, that is, to the minimum Lexicographic Order, there is no way to only enumeration, 3000 + MS is dangerous.
Snowflake snow snowflakes
Time limit:4000 Ms |
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Memory limit:65536 K |
Total submissions:26254 |
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Accepted:6900 |
Description You may have heard that no two snowflakes are alike. your task is to write a program to determine whether this is really true. your program will read information about a collection of snowflakes, and search for a pair that may be identical. each snowflake has six arms. for each snowflake, your program will be provided with a measurement of the length of each of the six arms. any pair of snowflakes which have the same lengths of corresponding arms shocould be flagged by your program as possibly identical. Input The first line of input will contain a single integerN, 0 <N≤ 100000, the number of snowflakes to follow. This will be followedNLines, each describing a snowflake. each snowflake will be described by a line containing six integers (each integer is at least 0 and less than 10000000), the lengths of the arms of the snow Ake. the lengths of the arms will be given in order around the snowflake (either clockwise or counterclockwise), but they may begin with any of the six arms. for example, the same snowflake cocould be described as 1 2 3 4 5 6 or 4 3 2 1 6 5. Output If all of the snowflakes are distinct, your program shocould print the message: No two snowflakes are alike. If there is a pair of possibly identical snow akes, your program shocould print the message: Twin snowflakes found. Sample Input 21 2 3 4 5 64 3 2 1 6 5
Sample output Twin snowflakes found. Source CCC 1, 2007 |
# Include <stdio. h> # Include < String . H> # Include <Iostream> Using Namespace STD; # Define N 1010000 # Define Mod4 1000007 # Define INF 10000001Typedef _ int64 ll; Struct Node { Int Next; Int G [ 6 ];} Edge [N]; Int CNT, pre [N]; Int Flag1; Void Hash (LL key, Int K [ 6 ]) { For ( Int P = pre [Key]; P! =- 1 ; P = Edge [p]. Next ){ Int FF = 0 ; For ( Int I = 0 ; I < 6 ; I ++ ) If (K [I]! =Edge [p]. g [I]) {FF = 1 ; Break ;} If (FF = 0 ) {Flag1 = 1 ; Return ;}} For ( Int I =0 ; I < 6 ; I ++ ) Edge [CNT]. g [I] = K [I]; edge [CNT]. Next = Pre [Key]; Pre [Key] = CNT ++ ;} Int Main (){ Int N; While (Scanf ( " % D " , & N )! =EOF ){ Int K [ 6 ], TK [ 6 ], MK [ 6 ]; CNT = 0 ; Memset (PRE, - 1 , Sizeof (Pre); flag1 = 0 ; For (Int I = 0 ; I <n; I ++ ){ For ( Int I = 0 ; I < 6 ; I ++ ) MK [I] = INF; For ( Int J = 0 ; J < 6 ; J ++) {Scanf ( " % D " ,& K [J]);} If (Flag1 = 1 ) Continue ; /* Int flag = 1; int T1 = s, T2 = s; For (Int J = 0; j <5; j ++) {T1 ++; if (T1> = 6) T1-= 6; T2 --; If (t2 <0) T2 + = 6; If (K [T1]> K [T2]) {flag =-1; // indicates reverse break;} If (K [T1] <K [T2]) {flag = 1; break ;}} for (Int J = 0; j <6; j ++) {TK [J] = K [s]; S + = flag; If (S> = 6) s-= 6; If (S <0) S + = 6 ;} */ For ( Int J = 0 ; J <6 ; J ++ ){ For ( Int I1 = 0 ; I1 < 6 ; I1 ++ ) TK [I1] = K [(I1 + J) % 6 ]; Int F = 0 ; For ( Int I1 =0 ; I1 < 6 ; I1 ++ ){ If (MK [I1] < TK [I1]) { Break ;} If (MK [I1]> TK [I1]) {f = 1 ; Break ;}} If (F = 1 ){ For ( Int I1 = 0 ; I1 < 6 ; I1 ++ ) MK [I1] = TK [I1] ;}} For ( Int J = 0 ; J < 6 ; J ++ ){ For ( Int I1 = 0 ; I1 < 6 ; I1 ++ ) TK [I1] = K (j-i1 + 6 ) % 6 ]; Int F = 0 ; For ( Int I1 = 0 ; I1 < 6 ; I1 ++ ){ If (MK [I1] < TK [I1]) { Break ;} If (MK [I1]> TK [I1]) {f = 1 ; Break ;}} If (F = 1 ){ For ( Int I1 = 0 ; I1 < 6 ; I1 ++ ) MK [I1] = TK [I1];} ll TMP = 0 ; For ( Int J = 0 ; J < 6 ; J ++ ) {TMP = (TMP * 100000007 + MK [J]) % MOD;} Hash (TMP, MK );} If (Flag1 = 0 ) Printf ( " No two snowflakes are alike. \ n " ); Else Printf ( " Twin snowflakes found. \ n " );} Return 0 ;}