POJ 3624 Charm Bracelet

Source: Internet
Author: User

http://poj.org/problem?id=3624

One-dimensional array of 01 backpack, V must be inverted enumeration, otherwise it will be placed the same item multiple times.

Charm Bracelet
Time Limit: 1000MS Memory Limit: 65536K
Total Submissions: 24456 Accepted: 11031

Description

Bessie have gone to the mall ' s jewelry store and spies a charm bracelet. Of course, she ' d like-to-fill it with the best charms possible from theN(1≤N≤3,402) Available charms. Each charm  i  in the supplied List has a weight  Wi   ( 1≤  Wi  ≤400), a ' Desirability ' Factor  Di   (1≤  Di  ≤100), And can is used at the most once. Bessie can only support a charm bracelet whose weight are no more than  M Span class= "Apple-converted-space" >  (1≤  M  ≤12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the MA Ximum possible sum of ratings.

Input

* Line 1:two space-separated integers: N and M * Lines 2.. N+1:line i+1 describes charm i with the space-separated integers: Wi and Di

Output

* Line 1: A single integer which is the greatest sum of charm desirabilities so can be achieved given the weight Constrai Nts

Sample Input

4 61 42 63 122 7

Sample Output

23
#include <iostream>#include<cstring>#include<cstdio>using namespacestd;intC,n;intv[3412],w[3412],f[12888];voidbackpack () {memset (f),0,sizeof(f)); inti,j;  for(i=1; i<=n;i++)       for(j=c;j>=0; j--)         if(j>=V[i]) f[j]=max (f[j],f[j-v[i]]+W[i]); printf ("%d\n", F[c]);}intMain () {inti; scanf ("%d%d",&n,&c);  for(i=1; i<=n;i++) scanf ("%d%d",&v[i],&W[i]);    Backpack (); return 0;}

POJ 3624 Charm Bracelet

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