Test instructions: give n cow, each cow has a hearing v, coordinate x, the energy between two cows for Max (V1,V2) *dist (V1,V2), the total energy value
Once each cow is sorted by the V, the order will find that the coordinates are smaller than the current x, and the coordinates are larger than the current x.
Assuming that the coordinates are smaller than x, there are num
So
The sum of distances = X*num-the sum of the preceding coordinates and +-(n-num-1) * x
And because
The and of the subsequent coordinates = the and of the entire interval coordinates-the and of the preceding coordinates
So with two arrays, one array to count, the other an array to count and
The study of this--http://www.acmtime.com/?p=403
1#include <iostream>2#include <cstdio>3#include <cstring>4#include <cmath>5#include <stack>6#include <vector>7#include <map>8#include <Set>9#include <queue>Ten#include <algorithm> One using namespacestd; A -typedefLong LongLL; - Const intINF = (1<< -)-1; the Const intMod=1000000007; - Const intmaxn=20005; - -LL A[MAXN];//This is for a number smaller than x . +LL B[MAXN];//This is used to ask for the front and - LL C[MAXN]; + intN; A at structnode{ - intx,v; - }Q[MAXN]; - - intCMP (node N1,node n2) { - returnN1.V <n2.v; in } - to intLowbit (intx) {returnX & (-x);} + -ll sum (ll c[],intx) { theLL ret=0; * while(X >0){ $RET + = c[x]; x-=lowbit (x);Panax Notoginseng } - returnret; the } + A voidAdd (LL c[],intXintd) { the while(X <MAXN) { +c[x]+=d;x+=lowbit (x); - } $ } $ - intMain () { -scanf"%d",&n); the for(intI=1; i<=n;i++) scanf ("%d%d",&q[i].v,&q[i].x); -Sort (q+1, q+n+1, CMP);Wuyi theMemset (A,0,sizeof(a)); -memset (b,0,sizeof(b)); WuLL cnt =0; - for(intI=1; i<=n;i++){ About intx = SUM (a,q[i].x);//How many of the statistical coordinates are smaller than x? $LL alltotal = SUM (B,MAXN);//to count all the coordinates of this interval and -LL total = SUM (b,q[i].x);//statistic The front coordinate is smaller than x and -CNT + = Q[I].V * (x * q[i].x-total + alltotal-total-(I-x-1) *q[i].x); -Add (a,q[i].x,1); A Add (b,q[i].x,q[i].x); + } theprintf"%i64d\n", CNT); - return 0; $}
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POJ 1990 Moofest "tree-like array"