Poj1321--dfs Backtracking

Source: Internet
Author: User

POJ 1321 DFS backtracking + recursive enumeration checkerboard issues
Time Limit: 1000MS Memory Limit: 10000K
Total Submissions: 24813 Accepted: 12261

Description

In a given shape of the chessboard (the shape may be irregular) on the top of the pieces, chess pieces no difference. If you need to place any of the two pieces in the same row or column in the chessboard, please program the chessboard with a given shape and size, and put all the feasible arrangement C for the K pieces.

Input

The input contains multiple sets of test data.
The first row of each set of data is two positive integers, n K, separated by a space, indicating that the chessboard will be described in a n*n matrix and the number of pieces to be placed. N <= 8, K <= N
When 1-1 indicates the end of the input.
The next n lines describe the shape of the chessboard: N characters per line, where # represents the board area. Represents an empty area (the data guarantees that no extra blank lines or blank columns appear).

Output

For each set of data, give a line of output, the output is placed in the number of programs C (Data Assurance c<2^31).

Sample Input

2 #.. #4 4...#. #.. #.. #...-1-1

Sample Output

21st

Idea: Using the method of N queen problem, Dfs backtracking is carried out in line order, and the feasible domain is recorded by the int type Vis array, and the increment and decrement control the change of feasible region. because K can be less than N, recursive enumeration is required; note border control, due to improper border control WA many times.
It took a couple of hours to finally AC.
//Poj1321--dfs Backtracking#include <iostream>#include<cstdio>#include<cstring>#include<cstdlib>#include<algorithm>using namespacestd;Const intmaxn= -;Const intInf= (1<< -);intn,k;intMAP[MAXN][MAXN];intCNT;voidPutintXinty) {     for(intI=1; i<=n;i++) {Map[i][y]++; Map[x][i]++; }}voidRemov (intXinty) {     for(intI=1; i<=n;i++) {Map[i][y]--; Map[x][i]--; }}voidSearchintCurintnum) {     for(intI=1; i<=n;i++){        if(Map[cur][i])Continue; BOOLflag=0; if(num==k) {CNT++; Flag=1;//The key to border control is here. You cannot return directly because the pieces you are placing are removed} put (cur,i); //Placing pieces        if(!flag) {             for(intj=cur+1; j<=n;j++) {Search (J,num+1); }} Remov (Cur,i); //Removing a pawn    }}intMain () { while(cin>>n>>k,n!=-1, k!=-1){         for(intI=1; i<=n;i++){             for(intj=1; j<=n;j++){                CharCh;cin>>ch; if(ch=='#') map[i][j]=0; Elsemap[i][j]=1; }} CNT=0;  for(intI=1; i<=n;i++) Search (i,1);//Recursive enumerationcout<<cnt<<Endl; }    return 0;}
Poj1321_dfs Backtracking

Poj1321--dfs Backtracking

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.