Poj1811 prime test, random prime number Test

Source: Internet
Author: User
Prime Test
Time limit:6000 ms   Memory limit:65536 K
Total submissions:24514   Accepted:5730
Case time limit:4000 Ms

Description

Given a big integer number, you are required to find out whether it's a prime number.

Input

The first line contains the number of test cases T (1 <= T <= 20), then the following T lines each contains an integer number N (2 <= n <254 ).

Output

For each test case, if n is a prime number, output a line containing the word "prime", otherwise, output a line containing the smallest prime factor of N.

Sample Input

2510

Sample output

Prime2


Miller_rabin Algorithm


# Include <cstdio> # include <cstring> # include <cmath> # include <ctime> # include <iostream> # include <algorithm> using namespace STD; typedef long ll; // rand (void) returns a random integer between [0, rand_max. // Random (n) returns a random integer between [0, N] ll random (ll n) {return (LL) (double) rand () /rand_max * n + 0.5);} inline ll mul_mod (ll a, LL B, ll c) {ll res = 0; A % = C; B % = C; for (; B; B >>= 1, A = (a <1) % C) {If (B & 1) RES = (RES + a) % C ;} return res;} ll pow_mod (ll a, LL B, ll c) {ll res = 1; for (; B; B> = 1, A = mul_mod (, a, c) {If (B & 1) RES = mul_mod (Res, a, c);} return res;} bool check (LL A, ll N, ll X, ll t) {ll ret = Pow_mod (A, X, n); ll last = ret; For (INT I = 1; I <= T; ++ I) {ret = mul_mod (Ret, RET, n); If (ret = 1 & last! = 1 & last! = N-1) return true; last = ret;} If (Ret! = 1) return true; else return false;} const int n = 8; bool miller_rabin (ll n) {If (n <2) return false; If (n = 2) return true; If (N & 1) = 0) return false; ll x = n-1; ll T = 0; while (X & 1) = 0) {x> = 1; t ++;} For (INT I = 0; I <n; ++ I) {ll A = random (X-2) + 1; if (check (A, n, x, t) return false;} return true;} ll factor [100]; int tol; ll gcd (ll a, LL B) {return B? Gcd (B, A % B): A> = 0? A:-A;} ll pollard_rov (ll x, ll c) {ll I = 1, K = 2; ll X0 = random (X-2) + 1; ll y = x0; while (1) {I ++; X0 = (mul_mod (x0, x0, x) + C) % x; ll d = gcd (y-x0, x); If (D! = 1 & D! = X) return D; If (y = x0) return X; if (I = k) {Y = x0; k + = K ;}}} void findfac (ll n, int K) {If (n = 1) return; If (miller_rabin (N) {factor [tol ++] = N; return ;} ll p = N; int c = K; while (P> = N) P = pollard_rov (p, c --); findfac (P, K); findfac (N/P, k);} int main () {int t; ll N; // srand (Time (null); // remove this sentence from G ++ on poj, A sad story .. Scanf ("% d", & T); While (t --) {scanf ("% LLD", & N); If (miller_rabin (n )) {printf ("prime \ n") ;}else {Tol = 0; findfac (n, 107); LL ans = factor [0]; for (INT I = 1; I <tol; ++ I) if (ANS> factor [I]) ans = factor [I]; printf ("% LLD \ n", ANS );}} return 0 ;}


Poj1811 prime test, random prime number Test

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.