poj2993 Flip 2996

Emag eht htiw Em Pleh

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 2944		Accepted: 1949

Description

This problem was a reverse case of the problem 2996. You are given the output of the problem H and your task was to find the corresponding input.

Input

According to output of problem 2996.

Output

According to input of problem 2996.

Sample Input

White:ke1,qd1,ra1,rh1,bc1,bf1,nb1,a2,c2,d2,f2,g2,h2,a3,e4black:ke8,qd8,ra8,rh8,bc8,ng8,nc6,a7,b7,c7,d7,e7,f7, H7,h6

Sample Output

+---+---+---+---+---+---+---+---+|. r.|:::|.b.|:q:|.k.|:::|.n.|:r:|+---+---+---+---+---+---+---+---+|:p: |.p.|:p: |.p.|:p: |.p.|:::|.p.| +---+---+---+---+---+---+---+---+|...|:::|.n.|:::|...|:::|...|:p: |+---+---+---+---+---+---+---+---+|:::|...|:: :|...|:::|...|:::|...| +---+---+---+---+---+---+---+---+|...|:::|...|:::|. p.|:::|...|:::|+---+---+---+---+---+---+---+---+|:P: |...|:::|...|:::|...|:::|...| +---+---+---+---+---+---+---+---+|. p.|:::|. p.|:P: |...|:P: |. p.|:P: |+---+---+---+---+---+---+---+---+|:r:|. n.|:b:|. q.|:k:|. b.|:::|. r.| +---+---+---+---+---+---+---+---+

Source

#include <stdio.h>
#include <string.h>
Char map[10][10],str1[100],str2[100];
int main () {
while (gets (str1)) {
Gets (STR2);
int Len1=strlen (STR1);
int Len2=strlen (STR2);
for (int i=0;i<=len1-1;i++) {
if (str1[i]>= ' 1 ' &&str1[i]<= ' 9 ') {
if (str1[i-2]!= ', ')
map[str1[i]-' 1 ' +1][str1[i-1]-' a ' +1]=str1[i-2];
Else
map[str1[i]-' 1 ' +1][str1[i-1]-' a ' +1]= ' P ';
}
}
for (int i=0;i<=len2-1;i++) {
if (str2[i]>= ' 1 ' &&str2[i]<= ' 9 ') {
if (str2[i-2]!= ', ')
map[str2[i]-' 1 ' +1][str2[i-1]-' a ' +1]=str2[i-2]+32;
Else
map[str2[i]-' 1 ' +1][str2[i-1]-' a ' +1]= ' P ';
}
}

printf ("+---+---+---+---+---+---+---+---+\n");
for (int i=8;i>=1;i--) {
printf ("|");
for (int j=1;j<=8;j++) {
if ((i+j)%2==0) {
printf (":");
if (Map[i][j]) printf ("%c", Map[i][j]);
else printf (":");
printf (":");
}
else {
printf (".");
if (Map[i][j]) printf ("%c", Map[i][j]);
else printf (".");
printf (".");
}
printf ("|");
}
printf ("\ n");
printf ("+---+---+---+---+---+---+---+---+\n");
}
memset (str1,0,sizeof (str1));
memset (str2,0,sizeof (str2));
memset (map,0,sizeof (map));
}
return 0;
}

poj2993 Flip 2996