Problem of set-up in circles

1. Given an orthopedic matrix matrix, print it in a circular fashion.

For example:

1 2 3 4

5 6 7 8

9 10 11 12

13 14 15 16

Printing results are:

1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10

Additional space complexity required: O (1)

Answer:

This paper mainly introduces a matrix processing method, this method can not only be used for this problem, but also suitable for many other face test, is the matrix lap processing. In the matrix with the upper-left corner of the TR,TC and the lower-right corner of the DR,DC can represent a sub-matrix, such as The Matrix in the title, when (TR,TC) = (0,0), (DR,DC) = (3,3), the matrix is the entire matrix, then the outermost part of this sub-matrix is as follows:

1 2 3 4

5 8

9 12

13 14 15 16

If the outer layer of the sub-matrix can be printed in circles, then (TR,TC) = (0,0), (DR,DC) = (3,3), the result is: 1 2 3 4 8 12 16 15 14 13 9 5. Next, the TR and TC are added 1, i.e. (TR,TC) = (1), so that the DR,DC minus the (DR,DC) = (2,2), the sub-matrix represented at this time is:

6 7

10 11

When the matrix is printed out, the result is: 6 7 11 10. Add TR,TC 1, i.e. (TR,TC) = (2,2), dr,dc minus 1, i.e. (DR,DC) = ((). The upper-left coordinate is found to the right or bottom of the bottom coordinate, and the whole process stops. The results that have been printed are the result of our request. The specific code reference is as follows:

1  Public voidSpiralorderprint (int[] matrix)2 {3     intTr=0;4     intTc=0;5     intDr=matrix.lenth-1;6     intDc=matrix[0].length-1;7Whiel (Tr<=dr && tc<=DC)8   {9Printedge (Matrix,tr++,tc++,dr--, dc--);Ten  One    } A } -   -   Public voidPrintedge (int[] Matrix,intTrintTcintDrintDC) the  { -     if(tr==DR) -   { -       for(inti=tc;i<=dc;i++) +System.out.print (m[tr][i]+ ""); -   } +  Else if(tc==DC) A  { at      for(inti=tr;i<=dr;i++) -System.out.print (m[i][tc]+ ""); -    } -}Else - { -     intCurc=TC; in     intCurr=tr; -      while(curc!=DC) to    { +System.out.print (m[tr][curc]+ ""); -Curc++; the     } *    while(curr!=DR) $  {Panax NotoginsengSystem.out.print (m[curr][dc]+ ""); -curr++; the   } +   while(curc!=TC) A    { theSystem.out.print (m[dr][curc]+ ""); +curc--; -     } $    while(curr!=TR) $  { -System.out.print (m[curr][tc]+ ""); -curr--; the   } -}

View Code

Problem of set-up in circles