First, List of common methods
list. Extend (L)
Extend the list by appending all the items in the given list; Equivalent to A[len (a):] = L.
list. Insert (i, x)
insert an item at a given position. The first argument is the index of the element before which to insert, SO a.insert (0, x) inserts at the front of the list, and a.insert (Len (a), x) is equivalent to a.append (x) .
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list. pop ( [ i ] )
remove the item at the given Position in the list, and return it. If No index is SPECIFIED, a.pop () removes and returns the last item in the list. (The square brackets around the I in the method signature denote that the parameter was optional, not th At your should type square brackets at that position. You'll see this notation frequently in the Python Library Reference.)
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list. sort ( cmp=none , key=none , reverse=false )
sort the items of the list in place (the arguments can is used for Sort customization, see sorted () for their explanation)
Example:
In [1]: a = [66.25, 333, 333, 1, 1234.5]in [2]: Print A.count (333), A.count (66.25), A.count (' X ') 2 1 0In [3]: A.insert (2,- 1) in [4]: A.append (333) in [5]: aout[5]: [66.25, 333,-1, 333, 1, 1234.5, 333]in [6]: A.index (333) out[6]: 1In [7]: A.remove (333) In [8]: A
OUT[8]: [66.25,-1, 333, 1, 1234.5, 333]in [9]: A.reverse () in [ten]: aout[10]: [333, 1234.5, 1, 333,-1, 66.25]in [all]: A.S ORT () in [aout[12]: [-1, 1, 66.25, 333, 333, 1234.5]in []: A.pop () out[13]: 1234.5In []: aout[14]: [-1, 1, 66.25, 3 33, 333]
Second, list as a stack
in [+]: stack = [3, 4, 5]in [+]: stack.append (6) in []: Stack.append (7) in []: stackout[18]: [3, 4, 5, 6, 7]in []: s Tack.pop () out[19]: 7In []: stackout[20]: [3, 4, 5, 6]in []: Stack.pop () out[21]: 6In []: Stack.pop () out[22]: 5
Third, list as queue
To use the queue efficiently, use the Collection.deque
In [All]: from collections import Dequein [+]: queue = deque (["Eric", "John", "Michael"]) in [+]: Queue.append ("Terry") in [+]: Queue.append ("Graham") in [+]: Queue.popleft () out[27]: ' Eric ' in [+]: Queue.popleft () out[28]: ' John ' in [29]: QUEUEOUT[29]: deque ([' Michael ', ' Terry ', ' Graham '])
Iv. common functions of programming
There are three built-in functions that are useful when used in conjunction with lists: Filter (), map (), reduce ()
The filter (function,sequence) function returns a set of sequences that contain elements that use function functions (sequence) to return a value that is true, and if sequence is a string or tuple, the result is the same type, Otherwise the result type is list:
in [+]: def f (x): return x% 3 = = 0 or x% 5 = = 0In [+]: Filter (F, Range (2)) out[31]: [3, 5, 6, 9, 10, 12, 15, 18, 20 , 21, 24]
Map (function,sequence) invokes function functions (sequence) for each element of the sequence sequence and returns a list of result groups:
in [+]: def cube (x): Return x*x*xin [+]: Map (cube, range (1, one)) out[33]: [1, 8, 27, 64, 125, 216, 343, 512, 729, 1000]
In [the]: seq = range (8) in [+]: def add (x, y): return x+yin [+]: Map (add, seq, seq) out[36]: [0, 2, 4, 6, 8, 10, 12, 14]
The reduce (function,sequence) function returns a single number as the result of the first number of calls to the function, and the result is a function call to the next element as a value:
In [PNS]: def add (x, y): return x+yin [+]: Reduce (Add, range (1, one)) out[38]: 55
In [MAX]: def sum (seq): ....: def add (x, y): Return x+y ....: Return reduce (add, seq, 0) ....: in [+]: Sum (RA Nge (1, one)) out[40]: 55In [in]: sum ([]) out[41]: 0
V. List parsing (listing comprehension)
The normal way to create a list is:
In [all]: squares = []in]: for x in range: ....: Squares.append (x**2) ....: in []: squaresout[44]: [0 , 1, 4, 9, 16, 25, 36, 49, 64, 81]
You can also create it in the following ways:
In [the]: squares = [x**2 for x in range (10)]
is also equivalent to:
in [+]: Squares = map (lambda x:x**2, Range (10))
in [+]: [(x, Y) for x in [All-in-A-z] for y in [3,1,4] if x! = y]out[47]: [(1, 3), (2, 3), (2, 1), (2, 4), (3, 1), (3, 4)]
Equivalent to:
In [to]: Combs = []in]: For x in []: ....: for y in [3,1,4]: ....: if x! = y: ....: Combs.append ((x, y)) ....: in [[]: Combsout[50]: [(1, 3), (1, 4), (2, 3), (2, 1), (2, 4), (3, 1), (3, 4)]
This article is from the "Ordinary Road" blog, please be sure to keep this source http://linjohn.blog.51cto.com/1026193/1611586
Python2.7 Self-study note 5--list