Python3 study notes-dictionaries and list exercises

First, the Dictionary practice _ registration Check

Requirement Point Description:

1. Use a dictionary to store existing user names, passwords

2, determine the input user name, password, confirm password can not be empty: strip ()

3. User name cannot be duplicated: key in Dirc

4, two times password should be input consistent

5, error 3 prompt error Too many times: for, Else

user = {    'Fengfeng':'123456',    'Fangfang':'456788'} forIinchRange (3): Username= Input ('Please enter user name'). Strip () passwd= Input ('Please enter your password'). Strip () cpasswd= Input ('Please enter your password again'). Strip ()ifUsernameinchUser#the dictionary uses in to judge the word, just to determine whether the key exists        Print('user name has been registered')    elifpasswd! =cpasswd:Print('two times the input password is inconsistent')    elifUsername = ="'orpasswd = ="' orCPASSWD = ="':        Print('the user name or password cannot be empty')    Else:        Print('Congratulations, the registration is successful!') User[username]=passwd#the dictionary inserts new data         BreakElse:    Print('excessive number of errors')Print(user)

Second, list practice

1. Verifying the user name is legal

Requirement Point Description:

1. Enter your account #input

2, if the account exists, the hint has been registered, if not exist, let him register #列表比对all_users [],count ()

3. Cannot be empty #strip ()

4. Length of user name length 6-12 len ()

5. Enter up to 3 times #循环

All_users = ['Fengfeng','Fangfang','Xiaofeng'] forIinchRange (3): User= Input ('Please enter user name:'). Strip ()ifLen (user) >5 andLen (user) <13:        ifAll_users.count (user) >0:Print('user name has been registered')        Else:            Print('user name is available, register it quickly')             Break    Else:        Print('user name length needs to be between 6-12 bits')Else:    Print('excessive number of failures')

1, two-dimensional list value

Requirement Point Description: Group the students who have handed in and do not hand in the job, and print

stus=[      ['Xiao Ming','Not delivered'],['Xiao Qing','has been handed'],      ['Small white','has been handed'], ['Little Violet','has been handed'],      ['Little Red','Not delivered'], ['Little Green','Not delivered'],      ['Xiao Huang','Not delivered'], ['Little Black','has been handed']]pass_list=[]#all the students who have handed in their homeworkFail_list=[]#students who do not hand in their homework forStuinchStus:status= Stu[1] Name=Stu[0]ifStatus = ='Not delivered': Fail_list.append (name)Else: Pass_list.append (name)Print('The student who has handed in the job is:%s, total%s personal'%(Pass_list,len (pass_list)))Print('non-handed jobs:%s, total%s personal'% (Fail_list,len (fail_list)))

Python3 study notes-dictionaries and list exercises