Python_ How do I call methods by instance method name?

Case:

In a project, our code uses the graphics classes in 2 different libraries:

Circle,triangle

Each of the two classes has a method interface that gets the area, but the interface has a different name

Requirements:

Unify these interfaces, do not care about the specific interface, as long as I call the Unified interface, the corresponding area will be calculated

How to solve this problem?

Defines a unified interface function that is called by reflection: GetAttr

#!/usr/bin/python3from Math Import Piclass Circle (object):    def __init__ (self, RADIUS):        Self.radius = Radius    def getarea (self):        return round (Pow (Self.radius, 2) * pi, 2) class Rectangle (object):    def __init__ (self, width, height):        self.width = width        self.height = height    def get_area (self):        return self.width * self.height# Definition Unified Interface def func_area (obj):    # Gets the string for the interface for    get_func in [' Get_area ', ' Getarea ']:        # Method of fetching by reflection C12/>func = GetAttr (obj, Get_func, None)        if func:            return func ()    if __name__ = = ' __main__ ':    c1 = CIRCL E (5.0)    r1 = Rectangle (4.0, 5.0)        # Returns an iterative object    Erea = Map (Func_area, [C1, R1]) through the map higher order function,    print (list ( Erea))

　　

Call by Methodcaller method in standard library operator

#!/usr/bin/python3from Math Import pifrom operator import Methodcallerclass Circle (object):    def __init__ (self, RADIUS):        Self.radius = Radius    def getarea (self):        return round (Pow (Self.radius, 2) * pi, 2) class Rectangle ( Object):    def __init__ (self, width, height):        self.width = width        self.height = height            def get_area (self)  :        return self.width * self.heightif __name__ = = ' __main__ ':    c1 = Circle (5.0)    r1 = Rectangle (4.0, 5.0)        # The first argument is the function string name, followed by the function required to pass in the arguments, execute parentheses in the incoming object    erea_c1 = Methodcaller (' Getarea ') (c1)    erea_r1 = Methodcaller (' get_ Area ') (R1)    print (EREA_C1, EREA_R1)

　　

Python_ How do I call methods by instance method name?