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Acdream1408: http: // 115.28.76.133/problem? PID = 1, 1408

Question: Let's give you an X, so that you can construct a and B. Yes, Na + BM can form all the numbers greater than X. A> 1, B> 1, but cannot form X.

Question: Sb at the beginning. All numbers (> = 2) can be composed of two and an odd number. SO 2 and x + 2 are a solution. And if X is an even number, this is unsolvable.

1 # include <iostream> 2 # include <algorithm> 3 # include <cstdio> 4 # include <cstring> 5 # include <vector> 6 using namespace STD; 7 int main () {8 long a; 9 While (~ Scanf ("% LLD", & A) {10 if (a % 2 = 0) printf ("0 0 \ n "); 11 else {12 printf ("% d % LLD \ n", 2, A + 2); 13} 14 15} 16 17 18}

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"Money, money, money"