"Usaco Open Gold" 2.Crisis on the Farm dynamic Regulation,

Test instructions: input n, m, p then n Cow Tower coordinates, m-haystack coordinates, p-order opportunity.

Each instruction can move up or down One direction, allowing all Nouta to be moved one unit at a time.

Then every haystack/Ox tower, there are 1 weights.

The maximum value of the weighted value and the maximum weight of the moving instruction sequence (minimum dictionary order).

F[i][j][k] Represents the first I, moving sequence x axis coordinates of J,y axis K, the maximum weight.

Then do it backwards to make sure the dictionary is ordered.

Code:

#include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #define N 1010# Define M 32#define inf 0x3f3f3f3fusing namespace std;int n,m,p;int map[n][n];int cx[n],cy[n];int lx=inf,rx,ly=inf,ry;int F[m][m<<1][m<<1],ans;char Opt[m][m<<1][m<<1];int Main () {//freopen ("test.in", "R", stdin); int I,j,k;int a,b,c;int x,y;scanf ("%d%d%d", &n,&m,&p), for (i=1;i<=n;i++) scanf ("%d%d", &cx[i], &cy[i]); for (i=1;i<=m;i++) {scanf ("%d%d", &x,&y); Map[x][y]=1;lx=min (lx,x), Rx=max (rx,x); Ly=min (ly,y ), Ry=max (ry,y);} for (i=p;i>=0;i--)//Walk I step {for (j=-i;j<=i;j++)//x-axis offset {int remain=i-abs (j); for (k=-remain;k<=remain;k++) {int Noxus=-1,demacia=0;char tt;for (int adc=1;adc<=n;adc++) {x=cx[adc]+j,y=cy[adc]+k;if (Lx<=x&&x<=rx &&ly<=y&&y<=ry&&map[x][y]) demacia++;} if (F[i+1][j+1+m][k+m]>noxus) noxus=f[i+1][j+1+m][k+m],tt= ' E '; if (F[i+1][j+m][k+1+m]>noxus) Noxus=f[i+1][j+M ][k+1+m],tt= ' N '; if (f[I+1] [J+m] [K-1+m]>noxus) noxus=f[i+1][j+m][k-1+m],tt= ' S '; if (f[i+1][j-1+m][k+m]>noxus) noxus=f[i+1][j-1+m][k+m],tt= ' W '; f[i][j+m][k+m]=noxus+demacia;opt[i][j+m][k+m]=tt;}}} printf ("%d\n", F[0][0+m][0+m]), X=y=0+m;for (i=0;i<p;i++) {printf ("%c", Opt[i][x][y]), if (opt[i][x][y]== ' E ') x + +; else if (opt[i][x][y]== ' W ') x--;else if (opt[i][x][y]== ' N ') y++;else if (opt[i][x][y]== ' S ') y--;} return 0;}

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"Usaco Open Gold" 2.Crisis on the Farm dynamic Regulation,