The question to consider is: the valid date, the number of days per month, and the leap year ....
1. valid date: the date and time between midnight on January 1, January 1, 0001 and 12:00:00 on January 1, December 31, 9999 in MSDN.
View http://msdn.microsoft.com/zh-cn/library/system.datetime (VS.80). aspx
2. Concept of a leap year: Baidu encyclopedia-four years a week, a hundred years not enough, four hundred years again
View http://baike.baidu.com/view/29649.htm
3. Integrated expression
Normal year:
The year can be written in a unified manner :(?! (0000) [0-9] {4}
The month of all years, including the Year of the same year, includes the day 1-28: (0 [1-9] | 1 [0-2]) -(0 [1-9] | 1 [0-9] | 2 [0-8])
All years, including the Year of the same year, except the Year of the same month, include the 29 and 30 days: (0 [13-9] | 1 [0-2])-(29 | 30)
All years, including year 1, 3, 5, 7, 8, 10, and December, contain 31 days: (0 [13578] | 1 [02])-31)
All the other dates except the February 29 of the leap year :(?! 0000) [0-9] {4}-(0 [1-9] | 1 [0-2]) -(0 [1-9] | 1 [0-9] | 2 [0-8]) | (0 [13-9] | 1 [0-2]) -(29 | 30) | (0 [13578] | 1 [02])-31)
Runnian
Year that can be divisible by 4 but cannot be divisible by 100: ([0-9] {2} (0 [48] | [2468] [048] | [13579] [26])
The year in which the object can be divisible by 400. The number that can be divisible by 400 is certainly 100, so the last two digits must be 00: (0 [48] | [2468] [048] | [13579] [26]) 00
The sum is the February 29 of all leap years: ([0-9] {2} (0 [48] | [2468] [048] | [13579] [26]) | (0 [48] | [2468] [048] | [13579] [26]) 00)-02-29)
All the four rules have been implemented and have no influence on each other. The combination is the regular expression of all dates that conform to the DateTime range.
^ ((?! 0000) [0-9] {4}-(0 [1-9] | 1 [0-2]) -(0 [1-9] | 1 [0-9] | 2 [0-8]) | (0 [13-9] | 1 [0-2]) -(29 | 30) | (0 [13578] | 1 [02])-31) | ([0-9] {2} (0 [48] | [2468] [048] | [13579] [26]) | (0 [48] | [2468] [048] | [13579] [26]) 00)-02-29) $
Considering that this regular expression is only used for verification, it is meaningless to capture a group. It only occupies resources and affects matching efficiency. Therefore, you can use a non-capture group for optimization.
^ (? :(?! (0000) [0-9] {4 }-(? :(? : 0 [1-9] | 1 [0-2])-(? : 0 [1-9] | 1 [0-9] | 2 [0-8]) | (? : 0 [13-9] | 1 [0-2])-(? : 29 | 30) | (? : 0 [1, 13578] | 1 [02])-31) | (? : [0-9] {2 }(? : 0 [48] | [2468] [048] | [13579] [26]) | (? : 0 [48] | [2468] [048] | [13579] [26]) 00)-02-29) $
For capture/non-capture of regular expressions, see: http://www.jb51.net/article/28035.htm
The last is the updated javascript method.
Copy codeThe Code is as follows: function checkDate (fname ){}
Copy codeThe Code is as follows: <body>
<Input type = "date" name = "textfield" id = "text1">
<Input type = "button" value = "button" onClick = "checkDate ('text1')">
</Body>
Correct Regular Expressions (including test code ): Copy codeCode: var str = '2017-12-33 ';
If (str. match (/^ ((? : 19 | 20) \ d)-(0 [1-9] | 1 [012]) -(0 [1-9] | [12] [0-9] | 3 [01]) $ /)){
Alert ('yesdate ');
} Else {
Alert ('not date ');
}
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