These two names are different, of course, the meanings they represent are different. I just started to see this scare, mainly Chinese is too broad and profound, the whole such abbreviation is too professional, people are around dizzy. It is easier to understand from the English explanation or the Chinese full name.
Pointer array: array of pointers, which is used to store pointers to arrays, which are arrays of elements that are pointers
Array pointer: A pointer to an array, which is a pointer to the array
Also note the differences in their usage, as illustrated below.
int* a[4] Pointer array
Expression: The elements in array A are INT-type pointers
Element means: *a[i] * (A[i]) is the same, because [] priority is higher than *
int (*a) [4] Array pointer
Represents: Pointer to array a
Element representation: (*A) [i]
Note: In practical applications, for pointer arrays, we often use this:
1 int* pInt; 2 pInt a[4];
This is the same as the meaning expressed in the pointer array definition above, except that the type transformation is taken.
The code demonstrates the following:
1#include <iostream>2 using namespacestd;3 4 intMain ()5 {6 intc[4] = {1,2,3,4};7 int*a[4];//Array of pointers8 int(*B) [4];//Array Pointers9B = &C;Ten //assigning an element in array C to array a One for(inti =0; I <4; i++) A { -A[i] = &C[i]; - } the //output look at the results -cout << *a[1] << Endl;//Output 2 is the right -cout << (*B) [2] << Endl;//Output 3 is the right - return 0; +}
Note: The array pointer is defined, the pointer to the first address of the array, the pointer must be given an address, it is easy to make the mistake is, do not give B address, directly with (*B) [i]=c[i] to the array B element assignment, when the array pointer does not know where to point, debugging may be correct, but the runtime must have problems, Be aware of this when using pointers. But why does a not have to give him the address, the element of A is a pointer, in fact the for loop has already given the element in the array a address. But if you write *a[i]=c[i in the For Loop], this also goes wrong. In short, the definition of the pointer must know where the pointer points, or tragedy.
Similar to the pointer function and function pointers, we have encountered.
Second, the key words of the pointer array and the difference between the set of pointers