Simple array manipulation string, encryption available

Source: Internet
Author: User
Tags chr
Encryption | array | String public Function ary (str)
Dim A ()
Dim B ()
Dim lenstr ' string length
Dim I, j ' Loop variable
Dim Ouflag
LENSTR = Len (str)
If lenstr Mod 2 = 1 Then
' The length is singular
Ouflag = False
LENSTR = lenstr + 1
ReDim A (2, LENSTR/2)
A (2, LENSTR/2) = Chr (20) ' last Fill space
Else
' Length is even
ReDim A (2, LENSTR/2)
Ouflag = True
End If
ReDim B (LENSTR/2, 2)
For i = 1 to Lenstr
If I <= lenstr/2 Then
A (1, i) = Mid (str, I, 1)
Else
If Ouflag = True Then
A (2, I-LENSTR/2) = Mid (str, I, 1)
Else
If I <> lenstr Then
A (2, I-LENSTR/2) = Mid (str, I, 1)
End If
End If
End If
Next
For i = 1 to 2
For j = 1 to LENSTR/2
B (J, I) = A (I, j)
Next
Next
For j = 1 to LENSTR/2
For i = 1 to 2
ary = ary & B (J, I)
Next
Next
If Ouflag = False Then
ary = left (ary, lenstr-1)
End If
End Function
Public Function unary (str)
Dim A ()
Dim B ()
Dim lenstr ' string length
Dim I, j ' Loop variable
Dim Ouflag
LENSTR = Len (str)
If lenstr Mod 2 = 1 Then
' The length is singular
Ouflag = False
LENSTR = lenstr + 1
ReDim A (LENSTR/2, 2)
A (LENSTR/2, 2) = CHR (20) ' last Fill space
Else
' Length is even
ReDim A (LENSTR/2, 2)
Ouflag = True
End If
ReDim B (2, LENSTR/2)
For i = 1 to Lenstr
If i = lenstr and Ouflag = False Then
A (LENSTR/2, 2) = ""
Else
If I Mod 2 = 1 Then
A ((i + 1)/2, 1) = Mid (str, I, 1)
Else
A (I/2, 2) = Mid (str, I, 1)
End If
End If
Next
For i = 1 to 2
For j = 1 to LENSTR/2
B (i, j) = A (j, i)
Next
Next
For i = 1 to 2
For j = 1 to LENSTR/2
unary = unary & B (i, J)
Next
Next
If Ouflag = Flag Then
unary = left (unary, lenstr-1)
End If
End Function

You'll know the use of it:
Dim Strg
Strg= "123456789"
Strg=ary (STRG)


Unary is decrypted.




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