SOJ 1036. Crypto Columns

Source: Internet
Author: User

Title: A string, minus the spaces and symbols to become "plaintext". Another string is called "keyword". The plaintext is lined up in rows, each row has a keyword.size width, and cannot be filled with a column filled with other characters, resulting in a character matrix. Each time you select the column that corresponds to the smallest dictionary order in the keyword, the selected character is no longer selected, and a new string is formed as the output string as the column of the matrix to be selected.
The idea of solving problems: sorting the characters in keyword and their corresponding columns, using sorting results to revert to a character matrix, and then output the character matrix by line.
The code is as follows:

1#include <iostream>2#include <string>3#include <vector>4 using namespacestd;5 6 Const intCOLS = the;7 Const intROWS = the;8 9 stringkw;Ten stringCT; One  A CharM[rows][cols]; -  - voidinit () { the      for(inti =0; i < ROWS; i++) { -          for(intj =0; J < COLS; J + +) { -M[I][J] =0; -         } +     } - } +  A structElem { at     Charch; -     intCol; - }; -  - Elem Elems[cols]; -  in BOOLcmpConstElem & E1,ConstElem &E2) { -     /*if (e1.ch > e2.ch) { to return true; + } else if (e1.ch < e2.ch) { - return false; the } else { * if (E1.col > E2.col) { $ return true;Panax Notoginseng } else if (E1.col < E2.col) { - return false; the } else { + return false; A         } the     }*/ +  -     return(e1.ch > e2.ch) | | (e1.ch = = e2.ch && e1.col >e2.col); $ } $  - intMain () { -     stringEnd ="theend"; the  -      while(Cin >> kw, kw! =end) {WuyiCIN >>CT; the         intc =kw.size (); -         intR = ct.size ()/kw.size (); Wu  -          for(inti =0; I < C; i++) { Aboutelems[i].ch =Kw[i]; $Elems[i].col =i; -         } -  -          for(inti =0; I < C; i++) { A              for(intj =0; J < C-i-1; J + +) { +                 if(CMP (Elems[j], elems[j +1])) { theElem Elem =Elems[j]; -ELEMS[J] = elems[j+1]; $elems[j+1] =Elem; the                 } the             } the         } the  -          for(inti =0; I < C; i++) { in             intBegin = R *i; the             //int end = begin + R; the             intCol =Elems[i].col; About  the              for(intj =0; J < R; J + +) { theM[j][col] = Ct[begin +j]; the             } +         } -  the          for(inti =0; I < R; i++) {Bayi              for(intj =0; J < C; J + +) { thecout <<M[i][j]; the             } -         } -  thecout <<Endl; the     } the  the     return 0; -}

SOJ 1036. Crypto Columns

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