Original
Author: Wang Bin 2005-04-06
With the first example, we have a little perceptual understanding of the spring framework, and now we have a complete description of the actual application of the spring framework through a specific login example! The IDE in this article is eclipse!
1. The Web server we use is Tomcat, so create a new catalog spring under D:\tomcat\webapps\webapps, and create a new two files below for Eclipse to import this project.
. classpath
<?xml version= "1.0" encoding= "UTF-8"?><classpath> <classpathentry kind= "src" path= "WEB-INF/src"/> <classpathentry kind= "Con" path= "Org.eclipse.jdt.launching.JRE_CONTAINER"/> <classpathentry "Output" Path= "Web-inf/classes"/></classpath>
. Project
<?xml version= "1.0" encoding= "UTF-8"?><projectdescription> <name>spring1</name> < comment></comment> <projects> </projects> <buildSpec> <buildCommand> <name> org.eclipse.jdt.core.javabuilder</name> <arguments> </arguments> </buildCommand> </ buildspec> <natures> <nature>org.eclipse.jdt.core.javanature</nature> </natures></ Projectdescription>
2. Under Spring, create a new directory Web-inf, and create a new file Web.xml,config.xml below so that Tomcat initializes spring
Xml
<?xml version= "1.0" encoding= "iso-8859-1" ><web-app xmlns= "HTTP://JAVA.SUN.COM/XML/NS/J2EE" Xmlns:xsi= "Http://www.w3.org/2001/XMLSchema-instance" xsi:schemalocation= "http://java.sun.com/xml/ns/j2ee Http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd " version=" 2.4 "> <servlet> <servlet-name>Dispatcher</servlet-name> <servlet-class> Org.springframework.web.servlet.DispatcherServlet </ Servlet-class> <init-param> <param-name>contextconfiglocation</ Param-name> <param-value>/WEB-INF/Config.xml</param-value> </init-param> </servlet> <servlet-mapping> < Servlet-name>dispatcher</servlet-name> <url-pattern>*.do</url-pattern> </sErvlet-mapping></web-app>
Config.xml
<?xml version= "1.0" encoding= "UTF-8"? ><! DOCTYPE beans Public "-//spring//dtd bean//en" "HTTP://WWW.SPRINGFRAMEWORK.ORG/DTD/SPRING-BEANS.DTD" >< beans> <!--Definition of View Resolver--> <bean id= "Viewresolver" class= " Org.springframework.web.servlet.view.InternalResourceViewResolver "> <property name=" Viewclass " > <value>org.springframework.web.servlet.view.jstlview </value> </property> < Property name= "prefix" > <value>/</value> </property> <property name= "suffix" > <value>.jsp</value> </property> </bean> <!--Request Mapping --> <bean id= "urlmapping" class= "org.springframework.web.servlet.handler.SimpleUrlHandlerMapping" > <property name= "Mappings" > <props> <prop key= "/login.do" >loginaction</prop> </pRops> </property> </bean>
<!---action definition--> <bean id= "loginaction" class= "action. Loginaction "> <property name=" Commandclass "> <value>action. logininfo</value> </property> <property name= "Fail_view" > <value>loginfail</value> & lt;/property> <property name= "Success_view" > <value>main</value> </property> </bean ></beans>
3. Create a new three directory src,classes,lib under Web-inf, as shown in
4. Import Spring in Eclipse
Ok,spring Import Complete!!!
5. Create three JSP files under the spring directory
index.jsp
<%@ page contenttype= "text/html; charset=gb2312 "%><%@ page language=" java "%><! DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 transitional//en" >
<form method= "POST" action= "login.do" ><p align= "left" > Login </p><br> Username: <input type= "Text" Name= "username" ><br> Password: <input type= "password" name= "password" ><br><p><input type= " Submit "value=" Name= "B1" ><input type= "reset" value= "reset" name= "B2" ></p></form>
</body>
main.jsp
<%@ page contenttype= "text/html; charset=gb2312 "%>
</body>
loginfail.jsp
<%@ page contenttype= "text/html; charset=gb2312 "%>
</body>
6. Under the Web-inf RC New package action, under the action package to create a new two Java files, note that in the project to import all the jar packages under E:pring\dist, otherwise the eclipse hint can not find the class file!
Logininfo.java
Package action;
public class Logininfo {private string username, private string password, public string GetPassword () {return password; public void SetPassword (string password) {This.password = password;} public String GetUserName () {return username;} public void Setusername (String username) {this.username = username;}}
Loginaction.java
Package Action;import Java.util.*;import Org.springframework.validation.*;import org.springframework.web.servlet.* ; Import org.springframework.web.servlet.mvc.*;
public class Loginaction extends Simpleformcontroller {private String fail_view;
Private String Success_view;
Protected Modelandview onSubmit (Object cmd, bindexception ex) throws Exception {Logininfo Logininfo = (logininfo) cmd ; if (login (logininfo) = = 0) {HashMap result_map = new HashMap (); Result_map.put ("Logininfo", logininfo); return new Modelandview (This.getsuccess_view (), result_map); else {return new Modelandview (This.getfail_view ()); } }
private int Login (Logininfo logininfo) {if ("QQQ". Equalsignorecase (Logininfo.getusername ()) && "1". Equals (log Ininfo.getpassword ()) {//assuming user name is "QQQ", password "1" return 0; return 1; }
Public String Getfail_view () {return fail_view;}
Public String Getsuccess_view () {return success_view;}
public void Setfail_view (string string) {Fail_view = string;}
public void Setsuccess_view (string string) {Success_view = string;}}
7. In the web-inf\lib under the e:pring\dist all jar packs, note that, but also from the Sun's Web site download Jstl.jar, or will appear
"Java.lang.noclassdeffounderror:javax/servlet/jsp/jstl/fmt/localizationcontext" Tips! The full picture is as follows (including the first example):
Ok! can now start Tomcat,ie input http://localhost/spring/index.jsp
Validation failed!
Verify success!
