The next + + operation in development is a puzzle

Post + + operations, tested in JavaScript and Java

var k = 0;

K = k++;

Console.log (k); 0

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int i = 0;

i = i++;

System.out.println (i);//0

Why the result is 0 instead of 1, the computer performs the second + + at the time of calculation,

If you need the result is 0, then need to use the front + +, this does not have to say, do not understand the test under their own

So let's look at one more case:

var k = 0;

k++;

Console.log (k);

What is the result of this? That's right, 1, don't get confused by the case above.

Why would that be?

The process of execution is top-down, then the second equals 1, which can understand

The first one is because the Post + + is executed later than the assignment, and when the discovery needs to be performed,

will be assigned to call first, after the execution of the + + operation, so you understand it

The next + + operation in development is a puzzle