The number of points of n dice of offer (43)

Question: Put n dice on the ground, all dice toward the sum of points on the top of S, input N, and print the probability of all possible values of S.

Int g_maxvalue = 6; // ================================== method 1 ========================== === void probability (INT number, int * pprobabilities); void probability (INT original, int current, int sum, int * pprobabilities); void printprobability_solution1 (INT number) {If (number <1) return; int maxsum = Number * g_maxvalue; int * pprobabilities = new int [maxsum-Number + 1]; for (INT I = number; I <= maxsum; ++ I) pprobabilities [I-number] = 0; probability (number, pprobabilities); int Total = POW (double) g_maxvalue, number); For (INT I = number; I <= maxsum; ++ I) {double ratio = (double) pprobabilities [I-number]/total; printf ("% d: % E \ n", I, ratio);} Delete [] pprobabilities;} void probability (INT number, int * pprobabilities) {for (INT I = 1; I <= g_maxvalue; ++ I) probability (number, number, I, pprobabilities);} void probability (INT original, int current, int sum, int * pprobabilities) {If (current = 1) {pprobabilities [Sum-original] ++;} else {for (INT I = 1; I <= g_maxvalue; ++ I) {probability (original, current-1, I + sum, pprobabilities );}}} // =================================== method 2 ======================== === void printprobability_solution2 (INT number) {If (number <1) return; int * pprobabilities [2]; pprobabilities [0] = new int [g_maxvalue * Number + 1]; pprobabilities [1] = new int [g_maxvalue * Number + 1]; for (INT I = 0; I <g_maxvalue * Number + 1; ++ I) {pprobabilities [0] [I] = 0; pprobabilities [1] [I] = 0;} int flag = 0; For (INT I = 1; I <= g_maxvalue; ++ I) pprobabilities [flag] [I] = 1; for (int K = 2; k <= number; ++ K) {for (INT I = 0; I <K; ++ I) pprobabilities [1-Flag] [I] = 0; For (INT I = K; I <= g_maxvalue * k; ++ I) {pprobabilities [1-Flag] [I] = 0; For (Int J = 1; j <= I & J <= g_maxvalue; ++ J) pprobabilities [1-Flag] [I] + = pprobabilities [flag] [I-j];} flag = 1-flag;} double Total = POW (double) g_maxvalue, number); For (INT I = number; I <= g_maxvalue * number; ++ I) {double ratio = (double) pprobabilities [flag] [I]/total; printf ("% d: % E \ n", I, ratio);} Delete [] pprobabilities [0]; Delete [] pprobabilities [1];}