In order to test the servlet, I wrote a simple login program with MyEclipse2015.
1. Login Page index.jsp.
1 <%@ Page Language="Java"Import="java.util.*"pageencoding="Utf-8"%>2 <%3 StringLusername= (String) Session.getattribute ("Iusername");4 %>5 6 <!DOCTYPE HTML PUBLIC "-//w3c//dtd HTML 4.01 transitional//en">7 <HTML>8 <Head>9 <MetaCharSet= "Utf-8">Ten <title>My JSP ' index.jsp ' starting page</title> One <Metahttp-equiv= "Pragma"content= "No-cache"> A <Metahttp-equiv= "Cache-control"content= "No-cache"> - <Metahttp-equiv= "Expires"content= "0"> - <Metahttp-equiv= "keywords"content= "Keyword1,keyword2,keyword3"> the <Metahttp-equiv= "description"content= "This is my page"> - </Head> - - <Body> + <% - if(lusername! )= ""&&lusername!=NULL) { + %> AWelcome,<%=Lusername%> at <% - } Else { - %> - <formname= "Loginfrm"Action= "Loginserv"Method= "POST"> -User name:<inputtype= "text"name= "username"value= "Zhangsan"><BR> -Password:<inputtype= "text"name= "Password"value= "mm123456"><BR> in <inputtype= "Submit"value= "Login"> - </form> to <% + } - %> the </Body> * </HTML>
2. Use the template to write a servlet program Loginserv.java.
1 PackageCom.kaly.servlet;2 3 Importjava.io.IOException;4 ImportJava.io.PrintWriter;5 6 Importjavax.servlet.ServletException;7 ImportJavax.servlet.http.HttpServlet;8 Importjavax.servlet.http.HttpServletRequest;9 ImportJavax.servlet.http.HttpServletResponse;Ten One Public classLoginservextendsHttpServlet { A Public voiddoget (httpservletrequest request, httpservletresponse response) - throwsservletexception, IOException { - DoPost (request, response); the } - - Public voidDoPost (httpservletrequest request, httpservletresponse response) - throwsservletexception, IOException { +Request.setcharacterencoding ("Utf-8"); -Response.setcontenttype ("text/html); Charset=utf-8"); +String Getuser=request.getparameter ("username"); AString getpassword=request.getparameter ("Password"); atPrintWriter pw=Response.getwriter (); - Pw.print (getUser); - } - -}
This is a very simple program, after receiving the request, the user name to print out.
3. Problem running: The requested resource is not available.
4. Find inquiries, not resolved. Later view Web. Xml.
1 <?XML version= "1.0" encoding= "UTF-8"?>2 <Web-appversion= "3.0"3 xmlns= "Http://java.sun.com/xml/ns/javaee"4 Xmlns:xsi= "Http://www.w3.org/2001/XMLSchema-instance"5 xsi:schemalocation= "Http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">6 <servlet>7 <Description>This is the description of my EE component</Description>8 <Display-name>This is the display name of my EE component</Display-name>9 <Servlet-name>Loginserv</Servlet-name>Ten <Servlet-class>Com.kaly.servlet.loginserv</Servlet-class> One </servlet> A - <servlet-mapping> - <Servlet-name>Loginserv</Servlet-name> the <Url-pattern>/servlet/loginserv</Url-pattern> - </servlet-mapping> - - </Web-app>
Because these are automatically generated, there is no thought of a problem. However, remember to write this program when the <url-pattern> node just before the <servlet-name> node content more than a "/", try to change it to/loginserv, restart the service run page. Some normal.
Summary: This should be one of the ways to solve this problem.
The requested resource is not available error in the servlet
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