To query a string with a pointer and replace the specified character in it

#define _crt_secure_no_warnings #include <stdio.h> #include <stdlib.h> #include &LT;STRING.H&G      
T A string that conforms to the following characteristics ("ABCD11111ABCD2222ABCDQQQQQ") requires writing a function (interface), outputting the following result//("ABCD"), and spreading the result;//More Highlights: http://      
                                www.bianceng.cnhttp://www.bianceng.cn/Programming/sjjg///Replace the string with (DCBA11111DCBA 2222DCBAQQQQQ) and spread the result. The number of occurrences//converted array is output//int getrestbuf (const char*buf1, int buflen, int *coun      
T, Char *buf2);      
    int getrestbuf (const char*buf1, int buflen, int *count, char *buf2) {int i=0;      
    int zcount = 0;      
    char *p1 = BUF1;      
    Char *psub = "ABCD";      
    Char buf[] = "DCBA";      
    This returns the number of occurrences//while (p1 = strstr (buf1//here should be the one you've picked up) Psub NULL) while (!= (P1=STRSTR))      
        {zcount++; Each time you find it, replace the string with "DCBA" or let the string correspond to the position you selected here is the assignment for (i = 0; I < sTrlen (psub);      
        i++) {* (p1 + i) = Buf[i];      
        } p1 = p1 + strlen (psub);      
        if (*p1 = = ' ") {break;      
    }//printf ("%d", p1);      
    } strcpy (Buf2, BUF1);      
    *count = Zcount;      
return 0;      
    } void Main () {int count = 0;      
    Char buf1[] = "ABCD11111ABCD2222ABCDQQQQQ";      
    int buflen = strlen (BUF1);      
    Char buf2[100];      
           
    Getrestbuf (BUF1, Buflen, &count, BUF2);      
    printf ("Find the number of strings is%d\n", count);      
    printf ("The original string is:%s\n", BUF1);      
    printf ("The replaced string is");      
    printf ("%s\n", buf2);      
System ("pause"); }