Two ways to throw a dice problem

About the two ways to throw the dice, just and a classmate chatting up,

I just made it. Two methods, all very simple!

In this record,

The first method is entered once each time:

#include <stdio.h>

#define N 5

int main () {

Define a variable to hold the number of dice

int num;

Define the number variables that appear

int count_1=0, count_2=0, count_3=0, count_4=0, count_5=0, count_6=0;

for (int i=1; i<=n; i++) {

printf ("Please enter the number of the dice to be thrown at%d times: \ n", i);

scanf ("%d", &num);

if (num==1) {

count_1++;

}else if (num==2) {

count_2++;

}else if (num==3) {

count_3++;

}else if (num==4) {

count_4++;

}else if (num==5) {

count_5++;

}else if (num==6) {

count_6++;

}//here because you entered it once, so you don't need to judge not 1-6,

}

printf ("1 occurrences of%d\n2 occurrences of the number of occurrences of the number of times%d\n3 appears%d\n4 the number of occurrences of the number of%d\n5 occurrences%d\n6 the number of occurrences%d\n", Count_1,count_2,count_3,count_4, Count_5,count_6);

return 0;

}

The second method, with random numbers:

#include <stdio.h>

#include <stdlib.h>

#define N 100

int main () {

int count_1=0, count_2=0, count_3=0, count_4=0, count_5=0, count_6=0;

for (int i=1; i<=n; i++) {

int num= Arc4random_uniform (6) +1; (N) The random 0~n-1,

if (num==1) {

count_1++;

}else if (num==2) {

count_2++;

}else if (num==3) {

count_3++;

}else if (num==4) {

count_4++;

}else if (num==5) {

count_5++;

}else if (num==6) {

count_6++;

}else{

i--;

Continue

}

}

printf ("1 occurrences of%d\n2 occurrences of the number of occurrences of the number of times%d\n3 appears%d\n4 the number of occurrences of the number of%d\n5 occurrences%d\n6 the number of occurrences%d\n", Count_1,count_2,count_3,count_4, Count_5,count_6);

return 0;

}

Two ways to throw a dice problem