Link: Ultraviolet A 1557-calendar game
Given a date, you can add a month or a day each time. The premise is that the next month has a corresponding date, for example, it is illegal to change from 1.30 plus one month to 2.30, and the maximum date is. Two people take turns and cannot perform the operation as a failure.
Solution: DP [y] [m] [d] indicates whether the corresponding date is the first day. You can do this in advance. Pay attention to the details, including the leap year. Share code.
#include <cstdio>#include <cstring>#include <algorithm>using namespace std;const int Y = 105;const int D = 15;const int M = 35;const int month[D] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};int dp[Y][D][M];bool is_year (int y) { if (y % 100 == 0 && y % 400 == 0) return true; if (y % 4 == 0 && y % 100) return true; return false;}int get_day (int y, int m) { if (y == 2001 && m == 11) return 4; if (m == 2 && is_year(y)) return 29; return month[m];}bool judge_day (int y, int m, int d) { if (y > 101) return false; if (y == 101 && m > 11) return false; if (y == 101 && m == 11 && d > 4) return false; return true;}bool getnext_day (int& yy, int& mm, int& dd, int y, int m, int d, int type) { if (type) { dd = d; mm = m + 1; if (mm > 12) { yy = y + 1; mm = 1; } else yy = y; if (dd > get_day(yy + 1900, m)) return false; } else { dd = d + 1; if (dd > get_day(y + 1900, m)) { dd = 1; mm = m + 1; } else mm = m; if (mm > 12) { yy = y + 1; mm = 1; } else yy = y; } return judge_day(yy, mm, dd);}int SG (int y, int m, int d) { if (dp[y][m][d] != -1) return dp[y][m][d]; dp[y][m][d] = 0; int yy, mm, dd; if (getnext_day(yy, mm, dd, y, m, d, 0)) { if (SG(yy, mm, dd) == false) dp[y][m][d] = 1; } if (getnext_day(yy, mm, dd, y, m, d, 1)) { if (SG(yy, mm, dd) == false) dp[y][m][d] = 1; } return dp[y][m][d];}void init () { memset(dp, -1, sizeof(dp)); dp[101][11][4] = 0; for (int i = 0; i <= 101; i++) { int limit_month = (i == 101 ? 11 : 12); for (int j = 1; j <= limit_month; j++) { int limit_day = get_day(1900+i, j); for (int d = 1; d <= limit_day; d++) SG(i, j, d); } }}int main () { init(); int cas, y, m, d; scanf("%d", &cas); while (cas--) { scanf("%d%d%d", &y, &m, &d); printf("%s\n", dp[y-1900][m][d] ? "YES" : "NO"); } return 0;}