Use XSD to determine elements and attributes in an XML file

As far as I know, ADO. Net does not seem to be able to implement this function. It uses XSD (schema) to judge the Data Type of the read node, but uses all the data as a string. The following class uses XSD to determine the data type of an element or attribute:

Using system;
Using system. IO;
Using system. xml;
Using system. xml. Schema;

Namespace REIT. aleis. xml
{
/// <Summary>
/// Reitxmldatavalidator is searched from an XSD File
/// Data type of an element or attribute and convert it to. NET data type
/// </Summary>
Public class reitxmldatatypefinder
{
Private XMLSCHEMA m_schema;

Public reitxmldatatypefinder (string xsdfilepath)
{
Filestream FS;
Try
{
FS = new filestream (xsdfilepath, filemode. Open );
M_schema = XMLSCHEMA. Read (FS, new validationeventhandler (showcompileerror ));
M_schema.compile (New validationeventhandler (showcompileerror); // compile it once
}
Catch
{
Throw;
}
}

Public System. Type findelementtype (string elementname)
{
System. xml. xmlqualifiedname name = new xmlqualifiedname (elementname, @ "http://www.reitweb.com/fc ");
Xmlschemaobject OBJ = m_schema.elements [name];
If (OBJ = NULL) return NULL;

Return findtype (OBJ );
}

Public System. Type findattributetype (string attributename)
{
System. xml. xmlqualifiedname attrname = new xmlqualifiedname (attributename, @ "http://www.reitweb.com/fc ");

Xmlschemaobject OBJ = m_schema.attributes [attrname];
If (OBJ = NULL) return NULL;

If (obj. GetType ()! = Typeof (xmlschemaattribute ))
Return NULL;

Xmlschemaattribute ATTR = (xmlschemaattribute) OBJ;
If (ATTR. attributetype! = NULL)
Return findtype (ATTR. attributetype );
Else
If (ATTR. schematypename. Name. compareto ("anytype") = 0) return typeof (object );

Return NULL;
}

Private Static void showcompileerror (Object sender, validationeventargs E)
{
Console. writeline ("validation error: {0}", E. Message );
}

private system. type findtype (Object OBJ)
{< br> If (obj. getType () = typeof (xmlschemasimpletype)
{< br> xmlschemasimpletype simpletype = (xmlschemasimpletype) OBJ;
return simpletype. datatype. valuetype;
}< br> else if (obj. getType () = typeof (xmlschemacomplextype)
{< br> xmlschemacomplextype complextype = (xmlschemacomplextype) OBJ;
return complextype. datatype. valuetype;
}< br> else
{< br> xmlschemadatatype datatype = (xmlschemadatatype) OBJ;
return datatype. valuetype;
}< BR >}

Posted on. NET refermer reading (2331) Comments (3) EDIT favorites reference favorites to 365key category: aleis Design

Comment:

# Re: Use XSD to judge the elements and attributes in the XML file at | what is the use of the xmlqualifiedname type ??

Not familiar with reply
# Re: Use XSD to determine the elements and attributes in the XML file. | Longping <? XML version = "1.0" encoding = "gb2312"?>
<Config>
<Field name = 'abscid' Title = 'absc No. 'inputbox = 'text' width = '000000' titlewidth = '000000'/>
<Field name = 'storeid' Title = 'database No. 'inputbox = 'text' width = '000000' titlewidth = '000000'/>
<Field name = 'uniteid' Title = 'uniform serial number 'inputbox = 'text' width = '000000' titlewidth = '000000'/>
<Field name = 'produproducingregion' Title = 'original' inputbox = 'text' width = '000000' titlewidth = '000000'/>
<Field name = 'breedregion' Title = 'conventional output' inputbox = 'text' width = '000000' titlewidth = '000000'/>
<List name = 'ref '>
<Column name = 'abscid'/>
<Column name = 'storeid'/>
<Column name = 'uniteid'/>
<Column name = 'produproducingare'/>
<Column name = 'breedare'/>
</List>
<Form name = 'Dialog 'Title = 'broad bean 'height = '000000' width = '000000'>
<Panel Cols = '2' border = '1'>
<Item name = 'abscid'/>
<Item name = 'storeid'/>
<Item name = 'uniteid'/>
<Item name = 'produproducingare'/>
<Item name = 'breedare'/>
</Panel>
</Form>
</Config>
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