Uvalive 3989 ladies 'choice

Classic stable marriage matching

Uvalive-3989ladies 'choice Time limit:6000 ms Memory limit:Unknown 64bit Io format:% LLD & % LlU [Submit] [Go Back] [Status] Description Problem I-Ladies? Choice Background Teenagers from the local high school have asked you to help them with the organization of next year? S prom. the idea is to find a suitable date for everyone in the class in a fair and civilized way. so, they have organized a web site where all students, boys and girls, state their preferences among the class members, by ordering all the possible candidates. your mission is to keep everyone as happy as possible. assume that there are equal numbers of boys and girls. Problem Given a set of preferences, set up the blind dates such that there are no other two people of opposite sex who wowould both rather have each other than their current partners. since it was decided that the prom was ladies 'choice, we want to produce the best possible choice for the girls. Input Input consists of multiple test cases the first line of the input contains the number of test cases. There is a blank line before each dataset. The input for each dataset consists of a positive integerN, Not greater than 1,000, indicating the number of couples in the class. Next, there areNLines, each one containing the all the integers from 1N, Ordered according to the girl? S preferences. Next, there areNLines, each one containing all the integers from 1N, Ordered according to the boy? S preferences. Output The output for each dataset consists of a sequenceNLines, whereI-thLine contains the number of the boy assigned toI-thGIRL (from 1N). Print a blank line between datasets. Sample Input 1   5 1 2 3 5 4 5 2 4 3 1 3 5 1 2 4 3 4 2 1 5 4 5 1 2 3 2 5 4 1 3 3 2 4 1 5 1 2 4 3 5 4 1 2 5 3 5 3 2 4 1 Sample output 1 2 5 3 4 Source Southwestern 2007-2008 [Submit] [Go Back] [Status]

#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#include <queue>using namespace std;const int maxn=1100;int n;int perfect_boy[maxn][maxn];int perfect_girl[maxn][maxn];int future_husband[maxn],future_wife[maxn];int next[maxn];queue<int> q;void engage(int boy,int girl){    int m=future_husband[girl];    if(m)    {        future_wife[m]=0;        q.push(m);    }    future_husband[girl]=boy;    future_wife[boy]=girl;}bool lover(int m1,int m2,int girl){    for(int i=1;i<=n;i++)    {        if(perfect_boy[girl][i]==m1) return true;        if(perfect_boy[girl][i]==m2) return false;    }}int main(){    int T_T;    scanf("%d",&T_T);    while(T_T--)    {        scanf("%d",&n);        memset(perfect_boy,0,sizeof(perfect_boy));        memset(perfect_girl,0,sizeof(perfect_girl));        memset(future_husband,0,sizeof(future_husband));        memset(future_wife,0,sizeof(future_wife));        memset(next,0,sizeof(next));        while(!q.empty()) q.pop();        for(int i=1;i<=n;i++)            for(int j=1;j<=n;j++)                scanf("%d",&perfect_girl[i][j]);        for(int i=1;i<=n;i++)        {            for(int j=1;j<=n;j++)                scanf("%d",&perfect_boy[i][j]);            q.push(i);        }        while(!q.empty())        {            int boy=q.front(); q.pop();            int girl=perfect_girl[boy][++next[boy]];            if(future_husband[girl]==0)                engage(boy,girl);            else            {                int m=future_husband[girl];                if(lover(boy,m,girl))                    engage(boy,girl);                else q.push(boy);            }        }        for(int i=1;i<=n;i++)            printf("%d\n",future_wife[i]);        if(T_T) putchar(10);    }    return 0;}