VB binary, octal, decimal, 16 conversion

Source: Internet
Author: User
octal | binary | decimal | hexadecimal | Convert public Function d_to_b (ByVal Dec as Long) as String
Todo
D_to_b = Dec Mod 2 & D_to_b
Dec = Dec \ 2
Loop while Dec
End Function

Public Function b_to_d (ByVal Bin as String) as Integer
Dim I as Long
For i = 1 to Len (Bin)
B_to_d = b_to_d * 2 + Val (Mid (Bin, I, 1))
Next I
End Function

Public Function H_to_b (ByVal Hex As String) as String
Dim I as Long
Dim B as String

Hex = UCase (Hex)
For i = 1 to Len (HEX)
Select Case Mid (Hex, I, 1)
Case "0": B = b & "0000"
Case "1": B = B & "0001"
Case "2": b = B & "0010"
Case "3": b = B & "0011"
Case "4": b = B & "0100"
Case "5": B = B & "0101"
Case "6": B = B & "0110"
Case "7": B = B & "0111"
Case "8": B = B & "1000"
Case "9": B = B & "1001"
Case "A": b = B & "1010"
Case "B": b = B & "1011"
Case "C": b = B & "1100"
Case "D": b = B & "1101"
Case "E": b = B & "1110"
Case "F": b = B & "1111"
End Select
Next I
While left (B, 1) = "0"
B = Right (b, Len (b)-1)
Wend
H_to_b = B
End Function

Public Function B_to_h (ByVal Bin As String) as String
Dim I as Long
Dim H as String
If Len (Bin) Mod 4 <> 0 Then
Bin = String (4-len (BIN) Mod 4, "0") & Bin
End If

For i = 1 to Len (Bin) Step 4
Select Case Mid (Bin, I, 4)
Case "0000": H = h & "0"
Case "0001": H = h & "1"
Case "0010": H = h & "2"
Case "0011": H = H & "3"
Case "0100": H = H & "4"
Case "0101": H = h & "5"
Case "0110": H = h & "6"
Case "0111": H = h & "7"
Case "1000": H = h & "8"
Case "1001": H = h & "9"
Case "1010": H = h & "A"
Case "1011": H = h & "B"
Case "1100": H = h & "C"
Case "1101": H = h & "D"
Case "1110": H = h & "E"
Case "1111": H = h & "F"
End Select
Next I
B_to_h = H
End Function




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