Want to comb the hands

(1) Use the function to find the largest value of a, B and in the order of large to small output

int MAX (int a,int b,int *p,int *q)

{

p=&a;//to write in the main function, the reason is not clear ... Anyway, to write the answer here is wrong, change to the main function is right, and can only define a main function or call function

q=&b;

if (a<b)

{

int c=a;//Anyway, *p is a, it's not standard, but it's right.

*p=b;

*q=c;

}

return A;

}

#include <stdio.h>

int main ()

{

int MAX (int a,int b,int *p,int *q)

int A, B;

int *p,*q;//should be int *p=a,*q=b;

Max (A,B,P,Q);

scanf ("%d%d", &a,&d);

printf ("%d\n", a);

printf ("%d%d", A, b);

return 0;

}

Error code, correcting://

Note: The definition is always *p, when called with P;

int *p=&a==int *p; p=&q;

Modified version:

If you change to a global variable:

Looks like me. The calling function is not on the front, and the global variable is best capitalized;

Suddenly think of a # define IP 3.14

(2) pointers and one-dimensional arrays

1.A[5] Output

#include <stdio.h>

int main ()

{

int a[5]={0,1,2,3,4};

int *p=a;//Note and the preceding difference int *p=&a; is the definition pointer p,p as address, the address is &a; but really should be int *p;int p=&a; But here, a represents the first address of a[5]

for (;p <a+5;p++)

printf ("%d", *p);

}

Want to input plus output

I don't know what's wrong, woo-hoo.

I came back and changed the wrong way.

Note that the current value of the pointer variable precedes the previous one that has been added to the a+5

Change the following, this is correct

Looks like I just saw this kind of.

Typical error

A is a constant cannot be ++;p a variable

Improved

P++;*p = = *p++ ==* (p++) ==a[i++]* and + + are the same priority, right-to-left, forget, later in the order of confusion, with parentheses

It's not too early to write tomorrow.

Want to comb the hands