Week 8 project 1 (3)

(3) define a fully defined class (it can be released as an independent product and become a "Basic Project" among many projects "). On the basis of (2), this type of class extends the functions of the +,-, *, And/operators so that it can perform operations with double data. If Complex C; double D; C + D and D + C are set, the result is "the plural number that treats D as the real part as D is added together with C". Other-, *, And/operators are similar.

/** Copyright (c) 2014, School of Computer and control engineering, Yantai University * All Rights Reserved. * dood luck * file name: D. CPP * Author: Zhang wanghua * Completion Date: July 15, April 29, 2015 * version number: V1.0 **/# include <iostream> using namespace STD; Class Complex {public: complex () {real = 0; imag = 0;} complex (Double R, double I) {real = r; imag = I;} friend complex operator + (const complex & C1, const complex & C2); friend complex operator-(const complex & C1, const complex & C2); friend complex operator * (const complex & C1, const complex & C2 ); friend complex operator/(const complex & C1, const complex & C2); friend complex operator + (const double & B, const complex & C2 ); friend complex operator-(const double & B, const complex & C2); friend complex operator * (const double & B, const complex & C2 ); friend complex operator/(const double & B, const complex & C2); friend complex operator + (const complex & C1, const double & B ); friend complex operator-(const complex & C1, const double & B); friend complex operator * (const complex & C1, const double & B ); friend complex operator/(const complex & C1, const double & B); void display (); Private: Double real; double imag ;}; // The following defines the member function complex operator + (const double & B, const complex & C2) {Complex C (B, 0); Return C + C2 ;} complex operator-(const double & B, const complex & C2) {Complex C (B, 0); Return c-c2;} complex operator * (const double & B, const complex & C2) {Complex C (B, 0); Return C * C2;} complex operator/(const double & B, const complex & C2) {Complex C (B, 0); Return C/C2;} complex operator + (const complex & C1, const double & B) {Complex C (B, 0); Return C1 + C ;} complex operator-(const complex & C1, const double & B) {Complex C (B, 0); Return c1-c;} complex operator * (const complex & C1, const double & B) {Complex C (B, 0); Return C1 * C;} complex operator/(const complex & C1, const double & B) {Complex C (B, 0); Return C1/C;} void complex: Display () {cout <"(" <real <"," <imag <") "<Endl;} complex operator + (const complex & C1, const complex & C2) {complex A;. real = c1.real + c2.real;. imag = c1.imag + c2.imag; return a;} complex operator-(const complex & C1, const complex & C2) {complex A;. real = c1.real-c2.real;. imag = c1.imag-c2.imag; return a;} complex operator * (const complex & C1, const complex & C2) {complex A;. real = c1.real * c2.real + c1.imag * c2.imag;. imag = c1.imag + c2.real + c1.real * c2.imag; return a;} complex operator/(const complex & C1, const complex & C2) {complex A; Double K; k = 1/(c2.real * c2.real + c2.imag * c2.imag);. real = (c1.real * c2.real + c1.imag * c2.imag) * k;. imag = (c1.imag + c2.real-c1.real * c2.imag) * k; return a;} // The main () function int main () {complex C1 (3, 4) used for testing is defined below ), c2 (5,-10), C3; double D = 11; cout <"C1 ="; c1.display (); cout <"C2 ="; c2.display (); cout <"d =" <D <Endl; cout <"the calculation result of the overload operator is as follows:" <Endl; C3 = C1 + C2; cout <"C1 + C2 ="; c3.display (); cout <"C1 + D ="; (C1 + D ). display (); cout <"d + C1 ="; (D + C1 ). display (); C3 = c1-c2; cout <"c1-c2 ="; c3.display (); cout <"c1-d ="; (c1-d ). display (); cout <"d-c1 ="; (d-c1 ). display (); C3 = C1 * C2; cout <"C1 * C2 ="; c3.display (); cout <"C1 * D ="; (C1 * D ). display (); cout <"D * C1 ="; (D * C1 ). display (); C3 = C1/C2; cout <"C1/C2 ="; c3.display (); cout <"C1/D ="; (C1/d ). display (); cout <"d/C1 ="; (D/C1 ). display (); Return 0 ;}

Running result:

Learning Experience:

I have been trying to find a simple method to implement heavy load. If I cannot find it, I should use this method first. I will know it later.

Week 8 project 1 (3)