Zoj 1414 number steps

Zoj
1414 number steps

Http://acm.zju.edu.cn/onlinejudge/showProblem.do? Problemcode = 1414.

According to the coordinate system given in the figure, give a coordinate and write the number on the coordinate. If it does not exist, output no number.

There are two rules:

1.
This rule and 2388 seem to have the same parity between the two numbers.

2.
When the two numbers are the same as the even number, the coordinate is required. When the two numbers are both odd, the coordinate and-1 are required.

The Code is as follows:

 

#include<stdio.h>int main(){int i,n,a,b;scanf("%d",&n);for(i = 1;i<=n;i++){scanf("%d%d",&a,&b);if((a+b)%2!=0){printf("No Number\n");continue;}if(a%2==0&&b%2==0)printf("%d\n",a+b);if(a%2!=0&&b%2!=0)printf("%d\n",a+b-1);}return 0;}